3.3. The Possible Black-Hole Solutions Of The Nuclear Matter
Next, we consider one negatively charged case again where some Fermi electron gas exists at the center of the black hole to check whether it could be a singularity at the center or not. It means negative charges are more than positive ones, and one situation is that the center consists of some neutral part and the Fermi electron gas. Equation (12) tells us that
Ue has infinite energy when
V0 is close to zero. However, electron gas cannot become a singularity point because it needs infinite energy revealed by Equation (8). When to discuss the gravitational collapse [
10,
11,
13], the Fermi electron gas is a good example to check whether the gravitational collapse is reasonable or not [
47].
Then we use a neutron star to discuss another possibility to form a black hole. Due to the supernova producing ultra-high pressure, most electrons and protons are supposed to react to turn into neutrons. After that, 2
N neutrons theoretically exist there. General Relativity is important in the high-density regions of the white dwarf and neutron stars. Considering the spherically symmetric metric, the general relativistic equations of hydrostatic equilibrium are the Tolman-Oppenheimer-Volkoff (TOV) form [31,48-53],
and
When discussing the neutron star, neutrons are the main roles. Theoretical studies of pure neutron matter derived from the nuclear many-body problem using two and three-body potentials fitted to laboratory measurements of nuclear properties by experimental nucleon-nucleon (NN) scattering data, give the density of nuclear matter inside a large nucleus like
208Pb ~
ns=0.16 nucleon/fm
3 or
ρs=2.7x10
14 g/cm
3 [33,51-53]. Based on these values, neutron stars with densities are estimated that up to ~ 7
ρs [
33]. However, it even reveals a prediction of the central pressure close to 625 MeV/fm
3 when the central density approximates 8.5
ρs calculated by the hadronic equation of state (EOS) [
33]. This central pressure value is equal to 10
35 Pascals, which is the same as the inside pressure of the proton experimentally reported [
35]. Therefore, we can expect the central density of a neutron star at least to be 8.5
ρs by considering the pressure equilibrium. On the other hand, it is reported that one demonstration of the hadronic EOS is consisting of two polytropes (i.e.,
p=
p0ργ) [
33], where
γ is the polytropic exponent, also called the adiabatic index [
54]. The two exponents
γ1=4/3, valid for the nuclear matter at densities below
ρs/3, and
γ2=3 are connected at the transition pressure
pt=
pn/8 and baryon density
ρs/2, where the pressure
pn=250 MeV/fm
3=10
35.8 dyne/cm
2 [
33]. According to these best-fit EOS parameters, it results in scaling between radius
R and mass
M as follows
or
If the proportional constant
K is considered in Equation (20
b), mathematically speaking, it will give possible conditions that this neutron star becomes a black hole at
R=
RS. Then the
R equation satisfying
R=
RS is given by
or
Explicitly, this expression reveals
RS dependent on the proportionality of
K and
γ, and has a singularity at
γ=2 which shall be avoided and unused. When
γ is determined, the smaller
K is, the larger
RS. Except for this, there is another division using three-polytropic pieces to fit a fixed-region EOS [52-54]. In this piecewise-polytropic EOS, each piece is specified by two parameters including the density
ρi and the polytropic exponents
γi for
i=1,2, and 3 [52-54]. These six parameters plus the core-crust transition density
ρ0 are a total of seven parameters used in this fitting EOS [
52]. In these pieces, the pressure
p and energy density
ε is continuous everywhere and the pressure and energy density within
ρi≧
ρ≧
ρi-1, for
i=1-2, and
ρ≧
ρi-1, for
i=3, satisfy [52-54]
and
where
A good fit is found for three polytropic pieces with fixed divisions at
ρ1=1.85
ρs and
ρ2=2
ρ1=3.70
ρs [
54]. The third density boundary
ρ3 is chosen to be 2
ρ2 [
52,
54]. Because
ρ0<
ρ1 is required in this polytropic-piecewise EOS, the value
ρ0=2x10
14 g/cm
3 is chosen as the first density parameter in the same reference [
53]. There is another choice of
ρ0 to be
ρs/2.7 or 10
14 g/cm
3 [
52]. The corresponding
p1,
p2, and
p3 for the EOS FPS are 10
34.283, 10
35.142, and 10
35.925 dyne/cm
2, respectively [
53]. The other parameters for the EOS AP3 are 10
34.392, 10
35.464, and 10
36.452 dyne/cm
2, respectively [
53]. Using these parameters, three polytropic exponents can be calculated for three polytropic pieces by applying Equation (24). Actually, not only
npeμ matter has been discussed, but also hyperons, pions, Kaon condensate, and quark matter have also been shown the parametrized EOSs [
53]. All the candidate EOSs perform very close to trends even some of them crisscross each other as shown in
Figure 2. Because the central pressure can be as high as 10
35 Pascals or 625 MeV/fm
3, the corresponding central mass density is 8.5
ρs at least. The three-polytropic EOS is bound by
ρ3=2
ρ2=7.4
ρs which is below our requirement. The
ρ-
p relation is even considered the central density of 20
ρs [
51]. Therefore, for simplicity, we adopt a unified model to describe the polytropic EOS for the neutron star as the red line plotted in
Figure 2, and it can extend to
ρ>9
ρs=2.43x10
15 g/cm
3. This polytropic EOS has the form
or
where
ρ0=
ρs/2.7=10
14 g/cm
3 and
p0=10
32.7 dyne/cm
2=0.2485 MeV/fm
3. In addition, the
γ=3 polytropic EOS is denoted by the yellow line [
51].
From Equation (26), it gives
Equation (27) can be solved numerically as long as the central density is given. On the other hand, substituting Equation (26) into Equation (18) directly gives the
m-
ρ relation
where
γ=2.8. Because (d
ρ/d
r)< 0 in the neutron star, the denominator is positive. Once d
ρ/d
r in Equation (27) is obtained, then
m(
r) in Equation (28) can be calculated where
ρ(
r) is evaluated by iteration based on the finite-difference method. In our simulations, the radial difference Δ
r of 10
-3 meter is used for calculations. This Δ
r is sufficiently convergent that the calculations of Δ
r=10
-1 are almost the same as those of Δ
r=10
-3. If the condition
is satisfied, then the neutron star can be treated as a non-rotating and uncharged black hole with a radius of r. Here the Schwarzschild radius RS is dependent on mass m(r) and radius r. When the equality in Equation (29) is considered, substituting Equation (28) into Equation (28) gives
If only the p-ρ relation like Equation (22) or Equation (26) is used, there is no solution of ρ(RS)=0 to the black hole for γ>=2, revealed in Equation (30). A reachable situation of ρ(RS)=0 at r=RS is given for γ<2. One possibility to fix this situation is to correct the expression of P(r) by adding one or more terms of order n with n<γ. A simple correction is to add a term of where k is a positive constant, and then Equation (30) becomes
and, mathematically speaking, it gives a few possible solutions including one at ρ(RS)=0. Then the m-ρ relation becomes
Except for ρ(r)=0, the other possible zero solutions in Equation (31) obey
or
which can give the possibility of r=RS in Equation (32). In Equation (34), it gives a solution of a Schwarzschild black hole if we can find the mass density such that
On the other hand, some demonstrations by using Equation (33) are shown in Figure 5 3. One
γ case is calculated and shown in
Figure 3, where the central density
ρc is between 2x10
18 and 1.1x10
19 kg/m
3. When
m(
r) in Equation (28) is applied, it is easy to do by changing the value of
γ. In this
γ case,
γ=2.80 in
Figure 3. The green line represents the star’s radius where
r=
RS. Since Equation (18) or (27) describes a non-rotating and uncharged star,
r=
RS is the limit of possible solutions due to the denominator.
Figure 3 exhibits
ρc=8x10
19 kg/m
3 corresponding to the most left curve and
ρc=1.1x10
19 kg/m
3 to the most right one so that the radius of the black hole at
ρc=8x10
19 kg/m
3 is smaller than that at
ρc=1.1x10
19 kg/m
3. In our calculations, the ratio of the star’s radius to
RS is 1.14365 at
ρc=1.1x10
19 kg/m
3 and 1.12547 at
ρc=8x10
19 kg/m
3. In all our calculations, the ratio is convergent to 1.125 as the previous report [
39].
3.4. Proposing Possible Blacks Hole With Finite-Size Nuclear Structures
When considering the charged effect, the exterior spacetime of a charged star can be described by the Reissner-Nordström metric [38-43,55-59]. The Einstein-Maxwell stress tensor of the isotropic fluid and electromagnetic field in terms of the Faraday–Maxwell tensor
Fμν=∂μAν−∂νAμ is [
39,
41,
42,
55,
56,
58,
59]
where Aμ is an electromagnetic four potential, uμ is the contravariant four-velocity of the fluid, ρc2 is the energy density of the fluid, and P is the isotropic pressure in the fluid. Consider the electric charge density ρe in the matter then the total charge is [40-43,55,56]
The above gravitational mass
m(
r) inside the sphere of radius
r represents the energy conservation as measured in the star’s frame. One can find that another of Einstein’s equations gives a differential equation for
m(
r), [
38,
39,
55,
58,
59]
Since
m(
r) represents the gravitational mass inside the sphere of a radius
r, then Equation (38) represents the energy conservation measured in the star’s frame [
39]. From the covariant conservation of the mass-energy stress tensor,
Tνμ;μ=0, one gets the hydrostatic equilibrium equation that determines the global structure of electrically charged stars. Then we obtain the modified TOV equation as [39,41-43,55,58,59]
Furthermore, if an incompressible fluid is considered, then
ρ(
r) is a constant whole of the body. Therefore, the energy density is also constant in the whole star. Based on this, the small electric-charge effect on mass is discussed next. As mentioned before, the zero-charge case in the Reissner–Nordström metric corresponds to the interior Schwarzschild structure. When a few electric charges exist in the star, the mass distribution is perturbed according to Equation (38). Then the charge
Q(
r) is treated as a small perturbation, and mass and charge are the forms [
39]
and
where
m0(
r) is the mass of the uncharged star, and
Q1(
r) and
m1(
r) are the perturbed small charge and mass distributions to be determined. Equation (41) reveals that the total mass in the electric-charge case is more than the uncharged case. Thus, the increasing mass can improve the optimized ratio of
r to
RS when a few electric charges are in the neutron star. Next, defining a characteristic length
Rc by [
39]
then the r-dependent mass within the sphere of a radius r is
where a dimensionless variable
x=
r/
Rc is introduced. It has been proved that the so-called Schwarzschild limit in an uncharged and non-rotating star gives [
39]
which is the same as the limit of our simulations that
R/
RS=1.125. Even more, the similar upper-ratio limit for the charged and non-rotating star has been given by [
60,
61]
where Q(R) is the total charge of the star. Suppose the electric charge density is proportional to the energy density in the smally charged effect, that is,
where
α is a proportional constant. Then the electric-charge distribution is given by [
39]
and the mass distribution is [
39]
if K=G=c=1 is used for natural units. Finally, Equation (44) becomes
In Equation (49), it seems that
α=0.4044 gives the value at the right side equal to 2.00 but is out of the small-charge range. Actually, it has been pointed out that this quasiblack hole configuration is given by the extremal charged case where
α is as high as 0.99 [
38]. On the other hand, a smaller value has been reported for a similar case, a charged perfect fluid model with high compactness [
62]. In this model, the minimum value in Equation (45) gives
which the radius of the compact star is smaller than the Schwarzschild radius. In this minimum condition, the total charge is and the one corresponding event horizon is
where
. In this reported case,
. According to this, a double-characteristic structure, based on the perfect fluids, is proposed to explain the existence of the black hole as shown in
Figure 4. This kind of black hole has a total charge zero or nonzero, and may have three regions or more. In this structure, the inner region denoted by I is a positively charged region and the almost whole mass of the black hole exists here, the middle region denoted by II is a neutrally thin region to protect the inside positive charges from easily electrically neutralizing the outside negative charges, and the outmost region denoted by III is a very thin negatively charged layer to balance the inner positive charges. One possible constitution in Region I is protons, which are covered by the neutral Region II consisting of materials such as neutrons. The appropriate metric used in Region I and Region II is the Reissner–Nordström metric. Kerr–Newman metric where Region I and Region II have no rotation. If the rotation is small so that the
RQ [
62] is a good approximation, then the Kerr-Newman metric can be used here. On the other hand, the appropriate metric outside Region III can be the Kerr-Newman metric because all charges enclosed by the outer dashed circle are zero or nonzero, and the total angular momentum is also zero or nonzero. Therefore, the charged term
RQ,new and rotation term
anew are both zero or nonzero dependent on the characteristics of Region III. The whole negative charges in Region III are supposed to move in circular orbitals and produce zero electric fields in Region I and Region II. Because the minimum radius is
for the case of the total charge
[
62], this negatively charged region can exist between
and
to ensure that the whole structure is within the Schwarzschild radius
RS. The amount of negative charges may be different from
Q to reach the criterion of a black hole. In such a case, the balanced total charge in Region III also changes. The most advantaged composition of Region III to form a black hole is the electron because its mass is only about 9.1 x10
-31 kg. However, there is a very strong Coulomb attraction between Region I and Region III. If Region III is initially at rest, it will be quickly attracted toward Region II and Region I. Therefore, one possible situation for Region III consisting of electrons is to move ultra-relativistically around Region I and Region II a little similar to the M87 black hole image surrounded by a hot disk accretion [
16]. The equatorial motions of charged test particles in the Kerr-Newman metric have been studied [63-67], in which the case of
l = 0 in the Kerr-Newman-Taub-NUT metric is also our research here. Based on these report [63-67], our model can have strongly support.
Then we start from the Kerr-Newman metric to discuss this model mentioned above. This starting point is chosen by the reason that Region III includes rotating charges, so it is better to describe the spacetime by the Kerr-Newman metric than the Reissner–Nordström metric which is only suitable for Region I and Region II. The Kerr-Newman metric is [
25,
44,
68]
where
and
The term related to angular momentum is
a =
J/
Mc. Three conservation constants of motions for a test particle of mass
m and electric charge
q can be obtained by Hamiltonian [
65,
66], which are
and
where the vector potential for electromagnetic fields is [65-67,69]
The equation of motion is
where . Using the general form of the Hamilton-Jacobi equation, the following differential equations governing the motion of the charged test particle can be deduced [63-67,70]:
and
where
is the affine parameter related to the proper time
τ of the particle divided by its mass
m [
63,
67,
70,
71], the Carter constant is zero here [63-65,70],
and
We consider the circular orbits in
Figure 4, where the satisfied conditions are
and
Three orbital configurations have been discussed at
,
, and
, where
and
are defined in the reference [
65]. From the latitudinal equation of motion, it follows that the circular orbit passing through
θ = 0 and
π only exists when
Q=0 [
63,
64]. Therefore, in our case of
Q ≠ 0, we simply consider the circular motion in the equatorial plane. In the case of particles with nonzero mass and a high specific charge, the above two conditions for the circular orbitals give two solutions for
E and
L, which are [
64,
65]
and
If the rotation of the charged test particle on the equatorial plane is counter-rotating, then the energy and angular momentum of the charged test particle are calculated with the sign ‘-’ in the above two equations. Otherwise, the sign ‘+’ is chosen if the charged test particle moves corotating. In this metric, the frame-dragging effect is
Although it exists in the Kerr-Newman source, the circular orbital can be corotating (prograde) and counter-rotating (retrograde) in the locally nonrotating frame [
64,
65,
67,
71]. Then we can calculate the energy
E and
L by using the known
a and
RQ. According to Ref. 62 [
62], the total charge
gives
In our model, we consider electrons moving in circular orbitals on the equatorial plane, surrounding Region I and Region II at radius r between 0.9367RS and RS, where Region I and Region II are static, so the rotation term is a=0 and the charged term is RQ=0.48RS in the E and L calculations. The spacetime in Region I and Region II is described by the Reissner–Nordström metric. Because the negative charges in Region III move ultra-relativistically surrounding Region I and Region II, the spacetime in and outside Region III is described by the Kerr-Newman metric. Therefore, the nonzero new rotation term anew exists which is produced by the surrounding negative charges. A simple choice of the negative charge in Region III is the electron whose mass is very tiny and only 9.1x10-31 kg, so we consider electrons as the negative charges in Region III.
Next, we discuss how to construct a finite-size structure to satisfy the criterion of a Kerr-Newman black hole. The event horizons of the Kerr-Newman black hole, determined by Δ=0, are
where r- is the inner event horizon and r+ is the outer horizon event. If the Kerr-Newman black hole is expected, then it needs r+≥Rmin=0.9367RS at least. In order to reach this criterion, small and small anew and RQ,new are better. Based on this, we use negative charges in Region III to balance the positive charges in Region I so the term RQ,new can be reduced to zero. However, due to the surrounding electrons, the nonzero angular momentum of electrons brings nonzero anew. For the purpose of decreasing the new rotation term anew, both corotating and counter-rotating electrons are considered. The simple situation is that the corotating and counter-rotating electrons are equal, and their total charges are -Q, . When the rotation term a of Region I and Region II is zero, the angular momenta of the corotating and counter-rotating electrons are the same in magnitude, which are
Therefore, if these two kinds of electrons are equal in number and move in opposite directions at very close orbitals, then the summation of their angular momenta is ~ 0. In the simple situation, we have anew~0 and RQ,new~0, so
In this case, the event horizon is larger than the radius of Region III and includes Region I and Region II. The number of total electrons is
N=1.029x10
39. As a result, a Kerr-Newman black hole with
anew=0 and
RQ,new=0, or a Schwarzschild black hole is formed by using our model in
Figure 4. In such a case, the radii of the counter-rotating and corotating electrons are denoted by
r1 and
r2, respectively. The radii satisfying
r+>=max(
r1,
r2) are drawn in
Figure 5(a), where the red points are the allowed radii for the whole structure including Region I, Region II, and Region III which can be black holes. More allowed radii are close to
Rmin=0.9367
RS, and the allowed radii decrease when they are close to
RS. On the other hand, the corresponding orbital energy and angular momentum for the counter-rotating (red) and corotating (green) electrons are plotted in
Figure 5(b) and 5(c), where the very small rotation term
a≦0.03
RS is considered with a constant
RQ=0.48
RS, and the radii are between 0.938
RS and 1.007
RS. Because the surrounding electrons are attracted by the positive charges, the orbital energy is negative no matter if it is a counter-rotating or corotating electron. Both kinds of electrons have the same energy when
a=0. In
Figure 5(c), the angular momenta show the counter-rotating electron has positive angular momentum and the corotating electron has negative angular momentum by definition. When
a=0, both kinds of electrons have the same angular momenta in magnitude.
Not only the Schwarzschild black hole but also the Kerr-Newman black hole can be formed in our model. Next, we consider the occupation of the counter-rotating electrons is α1N and the occupation of the corotating electrons is α2N, where α1≧0 and α2≧0, and α1 + α2 is not necessarily equal to one. If α1 + α2 <1. The finite-size structure including Region I, Region II, and Region III is positively charged. Otherwise, If α1 + α2 > 1, the finite-size structure is negatively charged. Therefore, if α1 + α2 ≠ 1, we have nonzero total charge Qnew=(1 - α1 - α2)Q and
If L1 is the angular momentum of the counter-rotating electron and L2 is the angular momentum of the corotating electron, then the total angular momenta are
and the new corresponding rotation term of the finite-size structure is
In order to have a small
anew, the values of
α1 and
α2 are expected to be close to each other. Some allowed radii of the counter-rotating and corotating electrons are plotted in
Figure 5(d), where
α1 is fixed at 0.50 and four different
α2 values, 0.28 (purple), 0.34 (cyan), 0.45 (green), and 0.62 (yellow) are chosen. As
α2 increases, the trend of the allowed
r2 decreases at the same
r1. In this case of
α1=0.50, the minimum
α2 is 0.277 by our calculations. In conclusion, our model can construct black hole and the property of the black hole is dominated by the corotating and counter-rotating electrons, which makes the black hole charged or uncharged, and rotating or non-rotating.
Furthermore, the Schwarzschild radius is linearly proportional to m(RS)=M so the average density of a black hole is
It shows that the average density is inversely proportional to the total mass square. Therefore, the higher the average density is, the lower the total mass and radius.
3.6. The Up Limit of The Nuclear Size In The Black Hole
In fact, it has been revealed that the upper-mass limit of the white dwarf star, calculated by the homogeneous-density model, is close to the inhomogeneous-density model by considering d
p/d
r and d
m/d
r [
45,
46]. The correction is to multiply the self-energy in the homogeneous-density model by a constant of 1.124 [
45,
46]. in such a compact star, the homogeneous-density model is a good approximation. Therefore, we can adopt the homogeneous density in both Equations (16) and (84) for the compact star. Furthermore, by ignoring the total energy of rest electrons, Equation (85) gives
where V=βV0 with 0<β<1. When α is small and considering the Taylor expansion to the linear term for , then Equation (86) becomes
After arranging the above equation, it gives
Then solving α, the range is
where the square root term is
This square root term depends on
N,
β, and
V0. All other parameters are well-known constants. This
α range approximately gives the exhaust of neutron particles in the event of a supernova. Equation (89) can estimate the mass of a black hole and its nuclear volume [
20] by considering the number of neutrons in the original star.
Then according to Equation (90), we demonstrate two situations and theoretically study the trend between the low limit
α and
β as shown in
Figure 5. The first situation is the star radius
r equal to
R☉, in which three cases of 2M
☉, 3M
☉, and 4M
☉ are considered in this situation. In our calculations, three curves for the three cases of the first situation are plotted in
Figure 5, and they are indigo (2M
☉), green (3M
☉), and red (4M
☉) curves from the left to the right. These three cases are also circled and denoted by
r=
R☉. The other three cases for the second situation circled and denoted by
r=0.1
R☉ in
Figure 5, are the indigo, green, and red curves corresponding to 2M
☉, 3M
☉, and 4M
☉ from the left to the right. The radius of each star in the first situation is 10 times larger than that of each star in the second situation. Therefore, in the second situation, the density of the star is 1,000 times larger than that of the star with the same mass in the first situation. In both situations, the curves of the lightest star (2M
☉) are at the most left and the curves of the heaviest star (4M
☉) are at the most right. In these curves, the low-limit
α means the minimum exhausting energy and
β represents the ratio of the final volume to the initial volume for each star experiencing supernova. If a smaller final volume is expected after a supernova, the exhausting energy has to be more than that of the larger final volume because a lot of exhausting energy is used to do work on compressing the initial volume to a smaller final one. In
Figure 5, the low-limit
α increases from 10% to 90% when
β decreases from about 10
-13 to 10
-19 for the 4-M
☉ case of the first situation, and from about 10
-10 to 10
-16 for the same case of the second situation. Theoretically speaking, the denser star needs more energy to compress itself to a smaller volume than a less dense star. For example, exhausting 10% mass or considering the low limit
α= 0.2 can reach a much smaller
β of about 10
-13 in the first situation than it in the second situation, where
β is about 10
-10, a much higher value. All these results are obtained by considering energy conservation.
Recently, the similarity between the neutron star and the black hole has been discussed [
47]. The compression of neutrons and helium atoms under extreme pressure has been studied [
72,
73]. Neutrons and protons are both baryons composed of quarks and gluons. They have much ability to change their sizes and the force inside them is the strong interaction which is 10
39 times larger than gravity. The experiment about the distribution of pressure inside the proton also showed the average peak pressure about of 10
35 Pascals near the center of a proton [
34]. This pressure much exceeds the pressure estimated by most neutron stars. When we compress the rest (2-
α)
N neutrons, they can become much smaller as shown in the quark-matter phase diagrams [
74,
75] and all the volume
V is within the event horizon of a black hole. In our discussions, we want to reveal the truth that the so-called curvature singularity inside the black hole, such as
r=0 in the Schwarzschild black hole, is a mathematical discussion in the Schwarzschild metric, not from physical foundation. In the traditional black-hole theory, the knowledge tells us that everything inside the black hole inevitably reaches
r=0 due to strong gravity, without considering any physical reality, and energy input and output. The evolution from the star to a black hole should follow energy conservation, and the black hole reasonably has a finite-size nucleus in it, not a singularity.
Figure 6.
A demonstration between α and β according to Equation (90). There are two groups plotted where the right group is 1,000 denser than the left group. Each group includes three cases where the mass of the star is 2M☉, 3M☉, and 4M☉ from left to right, and the radius of the star is the same in each case. The results show that the denser star wastes more energy to reduce its size at the same final volume.
Figure 6.
A demonstration between α and β according to Equation (90). There are two groups plotted where the right group is 1,000 denser than the left group. Each group includes three cases where the mass of the star is 2M☉, 3M☉, and 4M☉ from left to right, and the radius of the star is the same in each case. The results show that the denser star wastes more energy to reduce its size at the same final volume.