2. Ramsey Graphs Generated by Vector Fields
Consider vector field defined on
. Consider sets of six points
and six vectors related to these points
depicted in
Figure 1. Uppercase letters denote the coordinates of the points in
Origin of the vectors
is related to the points
) (actually, the vectors are seen as sliding ones, and the location of their origin is not important);
; lowercase letters denote the coordinates of the vectors (again, seen as sliding vectors). We define the set
as the set of vectors generating the complete bi-colored graph. Vectors
we denote as the “generators” of the Ramsey graph. The graph is built according to the following procedure. Points
serve as the vertices of the graph.
Vertices numbered
i and
j are connected with the red link, when Eq. 1 takes place:
And, correspondingly, the vertices numbered
i and
j are connected with the green link, when Eq. 2 occurs:
It is easily seen, that the exact location of the vectors/generators is not important, when the coloring procedure defined by Eqs. 1-2 is adopted. Vectors/generators themselves may be considered as the vertices of the graph. Vectors are “acquainted” each with another and they are connected with the red link, when Eq. 1 takes place, and vectors are “not acquainted” each with another, and they are connected with the green link, when Eq. 2 is true. The aforementioned procedure gives rise to the complete, bi-colored, Ramsey graph. Consider that the scalar product of vectors is independent of the system of coordinates; thus, the suggested coloring procedure defined by Eqs. 1-2 is invariant relatively to rotation of frames.
Let us illustrate the introduced procedure with
Figure 2, demonstrating two vectors
and
, belonging to the same plane. Sketch
A depicts the situation, where points “1” and “2” are connected with the red link, i.e.,
takes place; whereas, sketch
B depicts the situation, where points “1” and “2” are connected with the green link, i.e.,
takes place
The aforementioned mathematical procedure gives rise to the bi-colored, complete, Ramsey graph, such as that depicted in
Figure 3, supplied as an example.
According to the Ramsey theorem, this graph should necessarily contain at least one monochromatic (mono-colored triangle); due to the:
. Indeed, we recognize in
Figure 3 the green subgraph, labeled “345”; whereas, the triangles “123”, “124”,”125”, “126”, ”136”, “146”, ”156”, “236”, “246” and “256” are monochromatic red ones.
It should be emphasized that the introduced procedures of coloring, defined by Eqs. 1-2 are not transitive. In other words, if:
and
is assumed, it is not necessarily that:
. Let us illustrate this. Consider the planar system of vectors
, depicted in
Figure 4. Angles
are shown in
Figure 4. We adopt
, however
. Thus,
and
takes place. However,
is true (see
Figure 4). Thus, the introduced procedure of coloring of the graph edges is not transitive. The green-colored relation between the vectors/generators is also non-transitive; namely, if:
and
is assumed, it is not necessarily that:
This is important, due to the fact that the transitive Ramsey numbers are different from the non-transitive ones [
8,
9].
It is also should be stressed, that only directions of the generating vectors are important; the generating vectors may be considered as the unit ones. We finally come to following theorem.
Theorem: Consider set of the six vectors defined on Vectors are taken as the vertices of the graph. Vertices are connected with the red link, if: takes place, and they are connected with the green link if: The graph contains at least one monochromatic triangle.
3. Ramsey Graph Generated by the Ring-Like Systems of Generating Vectors
It will be instructive to demonstrate the introduced procedure of formation of bi-colored graphs with the ring-like system of generating vectors depicted in
Figure 5A. Five generating vectors
form pentagon. In this specific case, Eq. 5 is true:
The bi-colored graph generated by the vectors
according to Eqs. 1-2 is shown in
Figure 5B. The coloring of the graph follows Eqs. 1-2. Five generating vectors
serve as the vertices of the Ramsey graph.
Complete bi-colored graph shown in
Figure 5B does not contain any mono-colored triangle. Indeed, the Ramsey number
Now, consider the complete bi-colored graph generated by the ring-like system of six vectors
forming hexagon, shown in
Figure 6A. The bi-colored, complete Ramsey graph generated by the vectors
according to Eqs. 1-2, is shown in
Figure 6B. Again,
is true.
According to the Ramsey Theorem
this guarantees presence of at least one mono-colored triangle in the graph, presented in
Figure 6B. Indeed, triangles “135” and “246” appearing in
Figure 6B are green ones.
The suggested procedure is easily generalized for an arbitrary number of generating vectors. However, calculation of the large Ramsey numbers remains an unsolved problem.
Figure 1.
Six vectors defined on .
Figure 1.
Six vectors defined on .
Figure 2.
The coloring procedure is illustrated. Vectors and , belong to the same plane. A. . Points “1” and “2” are connected with the red link. B. . Points “1” and “2” are connected with the green link.
Figure 2.
The coloring procedure is illustrated. Vectors and , belong to the same plane. A. . Points “1” and “2” are connected with the red link. B. . Points “1” and “2” are connected with the green link.
Figure 3.
Bi-colored, complete graph generated by the vectors , and colored according to the Eqs. 1-2 is depicted. Vectors are the vertices of the graph. The coloring of the edges is carried out as follows: , , , , , , is true (see Eq. 1). is true (see Eq. 2).
Figure 3.
Bi-colored, complete graph generated by the vectors , and colored according to the Eqs. 1-2 is depicted. Vectors are the vertices of the graph. The coloring of the edges is carried out as follows: , , , , , , is true (see Eq. 1). is true (see Eq. 2).
Figure 4.
Triad of planar vectors is depicted. It is adopted: , however . Thus, and takes place. However, is true. The procedure of coloring of links defined by Eq. 1 is non-transitive.
Figure 4.
Triad of planar vectors is depicted. It is adopted: , however . Thus, and takes place. However, is true. The procedure of coloring of links defined by Eq. 1 is non-transitive.
Figure 5.
Ramsey complete bi-colored graph emerging from the system of five generating vectors forming pentagon. A. generating vectors are depicted. B. Complete bi-colored graph emerging from the system of generating vectors Eqs. 1-2 establish the green-red coloring of the graph. No monochromatic triangle is recognized.
Figure 5.
Ramsey complete bi-colored graph emerging from the system of five generating vectors forming pentagon. A. generating vectors are depicted. B. Complete bi-colored graph emerging from the system of generating vectors Eqs. 1-2 establish the green-red coloring of the graph. No monochromatic triangle is recognized.
Figure 6.
Ramsey complete bi-colored graph emerging from the system of six generating vectors forming hexagon. A. generating vectors, forming a ring are depicted. B. Complete bi-colored graph emerging from the system of generating vectors Eqs. 1-2 establish the green-red coloring of the graph. Triangles “135” and “246” are monochromatic.
Figure 6.
Ramsey complete bi-colored graph emerging from the system of six generating vectors forming hexagon. A. generating vectors, forming a ring are depicted. B. Complete bi-colored graph emerging from the system of generating vectors Eqs. 1-2 establish the green-red coloring of the graph. Triangles “135” and “246” are monochromatic.