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A peer-reviewed article of this preprint also exists.
This version is not peer-reviewed
Submitted:
20 September 2024
Posted:
23 September 2024
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1 | A linear operator is called bounded if and only if for any where the notation denotes the norm of on the space [5]. |
2 | An operator on the Hilbert space is called self-adjoint if it is operatorically identical to its adjoint, . The equivalence between two operators implies two conditions: for , and additionally the domains are identical,
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3 | The action of this operator, known as the time-ordering operator, is defined by , where is the Heaviside theta function. |
4 | We denote the exact solution by from the word pitaron which means solution in Hebrew. |
5 | The definition of this component is later provided in Equation (53). |
6 | Note that an operator is called a square root of operator if it satisfies . |
7 | Therefore, it is clear that the original terms in the perturbative series involving integrations in the iterative form , and not the productive form . |
8 | The integration over an operator is defined as where the inner integration includes any . Note that exchanging of the ordering of integrations, , is generally permitted only if is a bounded operator. |
9 | At first sight, the solution (9) seems to satisfy the Schrodinger equation. Indeed, by applying the derivative term-by-term based on , it seems that we arrive at
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10 | Essentially, we assume that both and . These non-trivial simplifications can only be guaranteed for bounded self-adjoint Hamiltonians integrted over a proper domain. |
11 | An additional operation that is not listed is the Fubini theorem, as mentioned in (14). However, it can be shown that this operation is redundant in terms of the mathematical requirements, as its validity is ensured if (17) is satisfied. In any case, it is clear that applying simplification (14) is not universal, and cannot be guaranteed to yield a correct transition if the integrand is conditionally convergent. |
12 | Contrary to the case of bounded operators, unbounded operators on a given space do not form an algebra, nor even a complete linear space [5]. Each unbounded operator is defined on its own domain, so that if and are two unbounded operators defined on the domains and respectively, then the domain of operator is . Note that two operators which act in the same way are to be considered as different if they are not defined on the same subspace of Hilbert space. According to Hellinger-Toeplitz theorem [5], if a self-adjoint operator is well defined on the entire Hilbert space it has to be bounded. |
13 | It is worth mentioning that one can ’save additivity’ by replacing the standard Riemann integral with a modified definition of integral, but obviously, this will not cure the fundamental problem, but rather just hide it inside the integrals definitions. |
14 | Otherwise, by tracing both sides of the relation, an illogical result is obtained [7]. |
15 | Similarly, . |
16 | The approximation is used. |
17 | The notation is introduced. Notice the difference with the definition of the norm: the outcome of is another operator, while the operation includes an additional tracing operation, and therefore, leaves us with just a number. |
18 | More generally, such a choice of Hamiltonian can be expressed by using a complete orthonormal Hilbert space , , where , with for any value of t. |
19 | Stating that if , then f is Riemann integrable if and only if f is bounded and the set of discontinuities of f has measure 0. |
20 | The notation of a broken arrow ↛ signifies here an invalid transition |
21 | For example, the value of is undefined. |
22 | Note that differentiation and conjugation are not commutative operations, , with equivalence only when using a self-adjoint Hamiltonian. |
23 | The simplification is used. |
24 | In order for operators and to represent an eligible decomposition of a diagonalizible Hamiltonian, they need to share a common set of eigenvectors. In that case they are simultaneously diagonalizable, which implies the relations . |
25 | In that case only the leading order term dominates the expansion of , . |
26 | So that, (A1) is essentially replaced by solving the system , that leads to . |
27 | Generally, if the signs of a and x are unknown, . |
28 | These are typically of the form with . For example, as discussed in [20], if the obtained result is given by for which approximate expressions cannot be found. |
29 | These are equtions of the type where is a self-adjoint operator. |
30 | By using the identity along with the observation that since the operator is fully expressible based on the operator they shares a common basis and domain,
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31 | More explicitly, . |
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