1. Introduction
Besides existence and uniqueness results, convergence results represent an important topic in Functional Analysis, Numerical Analysis, Differential and Partial Differential Equations Theory. Some elementary examples are the following: the continuous dependence of the solution with respect to the data, the convergence of the solution of a penalty problem to the solution of the original problem as the penalty parameter converges, the convergence of the discrete solution to the solution of the continuous problem as the time step or the discretization parameter converges to zero. Convergence results are important in the study of mathematical models which arise in Mechanics and Engineering Sciences, as well. Thus, the convergence of the solution of a contact problem with a deformable foundation to the solution of a contact problem with a rigid foundation as the stiffness coeficient of the foundation goes to infinity, the convergence of the solution of a viscoelastic problem to the solution of an elastic problem as the viscosity vanishes, the convergence of the solution of a frictional problem to the solution of a frictionless problem as the coefficient of friction converges to zero are simple examples, among others.
For all these reasons, a considerable effort was done to obtain convergence results in the study of various mathematical problems including nonlinear equations, inequality problems, fixed point problems and optimization problems, for instance. Most of the convergence results obtained in the literature provide sufficient conditions which guarantee the convergence of a given sequence to the solution of the corresponding problem, denoted in what follows by . In other words, these results do not describe all the sequences which have this property. Therefore, we naturally arrive to consider the following problem.
Problem .Given a metric space , a Problem which has a unique solution , provide necessary and sufficient conditions which guarantee the convergence of an arbitrary sequence to the solution u.
In other words, Problem consists to provide a convergence criterion to the solution of Problem .
Note that the solution of Problem
depends on the structure of the original problem
, cannot be provided in this abstract framework, and requires additional assumptions. Results in solving Problem
have been obtained in [
7] in the particular case when
is a variational inequality, in [
16] when
is a minimization problem as well as in [
17], in the case when
is a fixed point problem and an ordinary differential equation in a Banach or Hilbert space.
In this current paper we continue our research in [
7,
16,
17] with the case when
is an inclusion problem of the form
Here and below in this paper
K is a nonempty subset of a real Hilbert space
X,
represents the outward normal cone of
K,
is a nonlinear operator and
. Our study is motivated by possible applications in Solid and Contact Mechanics, among others. Indeed, a large number of constitutive laws in nonlinear elasticity and plasticity can be cast in the form (
1) and so do a number of mathematical models which describes the contact of a deformable body with a foundation. We shall provide such examples in the last two sections of the current paper. Moreover, we refer the reader to [
13] as well as to the recent book [
14] where inclusions of the form (
1) have been considered, together with various applications in Contact Mechanics.
The rest of the manuscrit is structured as follows. In
Section 2 we introduce some preliminary material. Then, in
Section 3 we state and prove our main result, Theorem 2. It provides necesssary and sufficient conditions which guarantee the convergence of a sequence
to the solution
u of the inclusion (
1). Next, in
Section 4 we apply Theorem 2 in order to deduce the continuous dependence of the solution with respect to the data
K,
A and
f, and to obtain a convergence result for a penalty problem, as well. In
Section 5 we use these convergence results in the study of a specific inclusion problem which describes the frictional contact of an elastic body with a foundation. Finally, in
Section 6 we provide an application of the abstract results in
Section 4 in the study of two elastic constitutive laws. We complete the results in
Section 5 and
Section 6 with various mechanical interpretations.
2. Preliminaries
Most of the preliminary results we present here can be found in many books or surveys. For the convenience of the reader we mention here the books [
1,
3,
9,
19,
20], for instance. There, details on the framework and notation we use as well as additional results in the field can be found.
Everywhere in this paper, unless it is specified otherwise, we use the functional framework described in Introduction. Therefore,
X represents a real Hilbert space endowed with the inner product
and its associated norm
. The set of parts of
X will be denoted by
and notation
and
will represent the zero element and the identity operator of
X, respectively. All the limits below are considered as
, even if we do not mention it explicitely. The symbols “⇀" and “→" denote the weak and the strong convergence in various spaces which will be specified, except in the case when these convergence take place in
. For a sequence
which converges to zero we use the short hand notation
. Finally, we denote by
the distance between the element
and the set
K, that is
For the convenience of the reader we also recall the following definition.
Definition 1. Let be a sequence of nonempty subsets of X and let K be a nonempty subset of X. We say that the sequence converges to K in the sense of Mosco ([11]) and we write , if the following conditions hold:
(a) for each , there exists a sequence such that for each and in X;
(b) for each sequence such that for each and in X, we have .
In the study of Problem (
1) we consider the following assumptions on the data.
Recall that in (
1) and below
is the outward normal cone of
K in the sense of convex analysis and
represents the projection operator on
K. Then, the following equivalences hold, for all
:
Therefore, using (
6) it follows that
This equivalence will be repeatedly used in the rest of the manuscript. Moreover, recall that the projection operator is monotone and nonexpansive, i.e.,
In addition, using assumption (
3) we deduce that for each
the following equality holds:
On the other hand, it is well known that conditions (4) implies that the operator is invertible and, moreover, its inverse
is a strongly monotone Lipschitz continuous operator with constants
and
, respectively. A proof of this result can be found in [
15, p. 23], for instance. Therefore, under assumption (4) the following inequalities hold:
The unique solvability of the inclusion (
1) is provided by the following existence and uniqueness result.
Theorem 1. Assume (3)–(5). Then there exists a unique element such that (1) holds.
Theorem 1 was proved in [
13] by using a fixed point argument. There, various convergence results to the solution of thus inequality have been proved and an example arising in Contact Mechanics has been presended.
We now proceed with the following elementary result which will be used in the next section.
Proposition 1.
Let K be a closed convex nonempty subset of X and let . Then, for each the solution of the inclusion (1) is given by
In addition, if K is the ball of radius 1 centered at , then
Proof. We use the equivalence (6) to see that, in the particular case when
,
u is a solution to (
1) if and only if
or, equivalently,
We now combine (16) and (7) to see that which proves (14).
Assume now that
K is the closed ball of radius 1 centered at
, i.e.,
Then, using (7) it is easy to see that
and, using (
14), we deduce (
15). □
Note that the solution of the inclusion (
1) depends on the data
A,
K and
f. For this reasons, sometimes below we shall use the notation
or
, for instance. This dependence was studied in [
14] where the following results have been proved.
Proposition 2.
Assume (3)–(5). Then the solution of inequality (1) depends continuosly on f, i.e., if denotes the solution of (1) with , for each , then
Proposition 3.
Assume (3)–(5). Then the solution of inequality (1) depends continuosly on K, i.e., if for each , is a non empty closed convex subset of X and denotes the solution of (1) with , then
Note that Propositions 2 and 3 provide sequences
which converge to the solution of the inclusion (
1). Nevertheless, these proposition do not describe all the sequences which have this property, as it results from the two elementary examples below.
Example 1. Consider the inclusion (1) in the particular case , , , and . Then, using (14) we deduce that the solution of inclusion (1) is . Let be the sequence given by for all . Then but we cannot find a sequence such that and . Indeed, assume that and . Then and, using the analytic expression of the function , we deduce that either or which contradicts the assumption . It follows from here that the convergence above cannot be deduced as a consequence of Proposition 2.
Example 2. Keep the same notation as those in Example 1. We claim that we cannot find a sequence such that and is the solution of the inclusion (1) with instead of K. Indeed, arguing by contradiction, assume that there exists such that and . Then . Therefore, is an interval of the form or with , . In both cases we arrive to a contradiction, since the Mosco convergence does not hold. We conclude that the convergence above cannot be deduced as a consequence of Proposition 3.
3. A convergence criterion
In this section we state and prove a convergence criterion for the solution of the inclusion (
1). To this end, under the assumption of Theorem 1, we denote by
u the solution of the inclusion (
1). Moreover, given an arbitrary sequence
, we consider the following statements:
Our main result in this section is the following.
Theorem 2. Assume (3)–(5). Then the statements (19) and (20) are equivalent.
Proof. Assume that (
19) holds and let
. Then, the regularity
implies that
and, using assumption (4)(b), we find that
Consider now an arbitrary element
. Then, using the identity
as well as inequality
in (
8) we find that
Note also that assumption (
19) implies that the sequence
is bounded in
X. Therefore, using assumption (4)(b) we deduce that there exists a constant
C which does not depeend on
n such that
We now combine inequalities (
22) and (
23) to see that
Denote
and note that, using assumption (
19) it follows that
Finally, we use (
26), (
25), (
21) and (
24) to see that (20) holds.
Conversely, assume that (20) holds. Let
and denote
Then, we have
and, using (
11), (20), we deduce that
We now take
in (
30) and
in (
8) to deduce that
and, adding these inequalities, we find that
Next, we use assumption (4)(a) on the operator
A to find that
Finally, we combine inequality (
31) with the convergences
and
, guaranted by (20) and (
29). As a result we deduce that
in
X, which concludes the proof. □
We remark that Theorem 2 provides an answer to Problem
in the particular case when Problem
is the inclusion problem (
1). Indeed, it provides a convergence criterion to the solution of this problem.
4. Some applications
Theorem 2 is useful to obtain various convergence results in the study of the inclusion (
1). In this section we present two types of such results : results concerning the continuous dependence of the solution with respect to the data and a result concerning the convergence of the solution of a penalty problem.
a)
We start with a continuous dependence result of the solution with respect to the data A and f. To this end we consider two sequences
and
such that
Then, using Theorem 1 it follows that for each
the exists a unique solution to the inclusion problem.
Moreover, the solution satisfies
Our first result in this section is the following.
Theorem 3. Assume (3)–(5) and (32), (33). Then in X.
Proof. Let
and
be fixed. We use inequality (
35) to write
and, using assumption (
32)(a),(c) we deduce that
It follows from here that
and, using assumptions (
32)(b), (33) we deduce that there exists
which does not depend on
n such that
Next, we use the regularity
in (
35), definition (
2) and assumption (
32)(a) to see that
and, using the bound (
36) we deduce that
Consider now an arbitrary element
and let
. Then, using the identity
as well as inequality in (
35) we find that
and, therefore,
We now use assumption (
32)(a) and the bound (
36) to deduce that
Denote
and note that, using assumptions (
32)(b), (33) it follows that
Finally, we use (
37)–(
40) to see that condition (20) is satisfied. We are now in a position to use Theorem 2 to deduce the convergence
in
X, which concludes the proof. □
b)
We proceed with a result which shows the dependence of the solution with respect to the set of constraints. To this end we consider two sequences of
and
such that
Then, we define the set
by equality
and, using Theorem 1 it follows that for each
the exists a unique solution
to the inclusion problem
Moreover, the solution satisfies
Our second result in this section is the following.
Theorem 4. Assume (3)–(5) and (41), (42). Then in X.
Proof. We use Theorem 2 and, to this end we check in what follows that condition (20) is satisfied. Let
. Since
it follows from (
42) that there exists
such that
which implies that
Therefore,
which implies that
Now, using (
42) and arguments similar to those used in the proof of inequality (
36) we find that the sequence
is bounded in
X and, therefore, there exists
which does not depend on
n such that
Thus, it follows from (
46) that
Assume now that
. We write
and, since
, using (
44) we deduce that
We now combine (
49) and (
50) to see that
and, using (
47) we find that
Denote
and note that, using assumptions (
41), it follows that
Finally, we use (
53), (
52), (
48) and (
51) to see that condition (20) is satisfied. We are now in a position to use Theorem 2 to deduce the convergence
in
X which concludes the proof. □
c)
We now present a convergence result concening a penalty method. To this end we consider a numerical sequence
such that
together with the problem of finding
such that
Our third result in this section is the following.
Theorem 5. Assume (3)–(5) and (54). Then, for each equation (55) has a unique solution. Moreover, in X.
Proof. The proof is structured in several steps, as follows.
Step i) We prove the unique solvability of equation (55). Let
,
and denote
Then, since
is invertible, we have
Using these equalities it is easy to see that
is a solution of equation (
55) if and only if
is a solution of the equation
Consider now the operator
defined by
Then, using the properties (
9), (10) and (
12), (13) of the operators
and
A, it is easy to see that the operator
is strongly monotone and Lipschitz continuous with constants
and
, that is
Therefore, it is invertible and its inverse, denoted by
, is defined on
X with values in
X. We conclude from here that there exists a unique element
such that
. Using now the definition (
59) we obtain the unique solvability of the nonlinear equation (
58) and, equivalently, the unique solvability of the nonlinear equation (
55).
Step ii) We prove the boundedness of the sequences and . Let
and let
be a fixed element in
K. We use (
60) to deduce that
and, since
,
, we find that
which proves that the sequence
is bounded in
X. This implies that the sequence
is bounded in
X and, using (
57) we deduce that
is a bounded sequence in
X which concludes the proof of this step.
Step iii) We prove the inequality
Let
and
. We use (
56)–(
58) and equality
to see that
which shows that
Recall that
and, moreover, (10) implies that
Therefore, using (
63) we deduce that (
62) holds.
Step iv) We prove that there exists such that
Let
. We use (
56) and (
58) to see that
On the other hand, it follows from the proof of Step ii) that the sequence
is bounded in
X. Therefore, using the properties of the operator
we deduce that there exists
which does not depend on
n such that
Inequality (
64) is now a consequence of relations (
65) and (
66).
Step v) End of proof. We now combine inequalities (
62) and (
64) with assumptions (
54) to see that condition (20) is satisfied with
. Finally, we use Theorem 2 to conclude that the convergence
in
X holds. □
5. An example in Contact Mechanics
In this section we apply the abstract results in
Section 3 and
Section 4 in the variational analysis of a mathematical model which describes the bilateral contact between an elastic body and a foundation. The classical formulation of the problem is the following.
Problem .Find a displacement field and a stress field such that
Here () is a domain with smooth boundary divided into three measurable disjoint parts , and such that . It represents the reference configuration of the elastic body. Moreover, is the unit outward normal to , denotes the space of second order symmetric tensors on and, below, we use the notation “”, , 0 for the inner product, the norm and the zero element of the spaces and , respectively. A generic point in will be denoted by .
We now provide a short description of the equations and boundary conditions in Problem
and send the reader to [
2,
5,
6,
8,
10,
12] for more details and comments. First, equation (
67) represents the constitutive law of the material in which
is the elasticity operator and
denotes the linearized strain tensor. Equation (68) is the equilibrium equation in which
denotes the density of body forces acting on the body. The boundary condition (69) is the displacement condition which models the fact that the body is held fixed on the part
on its boundary. Condition (70) is the traction boundary condition. It models the fact that a traction of density
is acting on the part
of the surface of the body. The boundary conditions (71) and (72) are the interface laws on
where the body is assumed to be in contact with an obstacle, the so-called foundation. Here
and
denote the normal and the tangential displacement, respectively, and
is the tangential part of the stress vector
. Condition (71) shows that the contact is bilateral, i.e., there is no separation between the body and the foundation. Finally, condition (72) represents the Tresca friction law, in which
g denotes the friction bound.
In the analysis of Problem we use the standard notation for Sobolev and Lebesgue spaces associated to and . In particular, we use the spaces , and , endowed with their canonical inner products and associated norms. Moreover, for an element we still write v for the trace of v to and we denote by and its normal and tangential components on given by and . In addition, recall that with .
Next, for the displacement field we need the space
V and for the stress and strain fields we need the space
Q, defined as follows:
The spaces
V and
Q are real Hilbert spaces endowed with the inner products
Here and below
represents the deformation operator, i.e.,
where an index that follows a comma denotes the partial derivative with respect to the corresponding component of
x, e.g.,
. The associated norms on these spaces will be denoted by
and
, respectively. Recall that the completeness of the space
follows from the assumption
, which allows the use of Korn’s inequality. Note also that, by the definition of the inner product in the spaces
V and
Q, we have
In the study of Problem
we assume that the operator
satisfies the following condition.
Moreover, the density of body forces and the friction bound are such that
Assume now that
represents a couple of regular functions which satisfy (
67)–(72). Then, using standard arguments it follows that
We now introduce the operator
, the functional
the element
and the set
K defined by
Then, using (
78) and notation (80), (81) we obtain that
We now test in (
83) with
and
to see that
Therefore, using (
83) and (
84) we find that
This inequality combined with the definition (82) implies that
To proceed, we use (82) and (
84) to see that
and, using notation
for the strain field, we find that
On the other hand, the constitutive law (
67), definition (
79) and equality
show that
and, therefore,
We now combine (
85)–(
87) to deduce that
Finally, inequality (
88) and (
6) lead to the following variational formulation of Problem
, in terms of the strain field.
Problem.
Find a strain field such that
We now consider the sequences
,
,
such that, for each
, the following hold.
Then, for each
we consider the element
and the set
given by
together with the following problem.
Problem .
Find a strain field such that
Our main result in this section is the following.
Theorem 6. Assume (75)–(77), (90) and (91). Then, Problem has a unique solution and, for each , Problem has a unique solution . Moreover, if (92) and (93) hold, then in Q.
Proof. For the existence part we use Theorem 1 on the space
. First, we note that
and, since
for each
, using definition (82) we deduce that
and, therefore,
K is nonempty. On the other hand, it is easy to see that
K is a convex subset of
Q. We conclude from here that condition (
3) is satisfied. In addition, using assumption (
75) we see that
for all
. Therefore, condition (4) holds with
and
. We are now in a position to use Theorem 1 with
to deduce the unique solvability of the inclusion (
89). The unique solvability of the inclusion and (
96) follows from the same argument.
Assume now that the convergences (92) and (93) hold. Then, using the definitions (
94) and (81) it is easy to see that
in
V and, therefore, (
74) implies that
On the other hand using the definitions (82) and (95) of the sets
K and
together with equality (
97), it is easy to set that the following equivalence holds, for each
:
It follows from here that condition (
42) is satisfied. Moreover, the convergences (93) and (
98) guarantee that the sequences
and
defined above satisfy conditions (
41). The convergence result in Theorem 6 is now a direct consequence of Theorem 4. □
In addition to the mathematical interest in this theorem, it is important from mechanical point of view since it shows that the weak solution of the contact problems depends continuously on the density of body forces, the density of traction forces and the friction bound, as well.
6. An application in Solid Mechanics
In this section we provide an example of inclusion in Solid Mechanics for which the results in Theorem 5 work. More precisely, we introduce and analize two nonlinear constitutive laws for elastic materials. To this end, again, we use notation
for the space of second order symmetric tensors on
with
and recall that the indices
i,
j,
k,
l run between 1 and
d. Our construction below is based on rheological arguments which can be found in [
4], for instance.
The first constitutive law is obtained by connecting in parallel an elastic rheological element with a rigid-elastic one with constraints. Therefore, we have an additive decomposition of the total stress
, i.e.,
Here
is the stress in the elastic element and
is the stress in the rigid-elastic element with constraints. We denote by
the strain tensor and we recall that, since the connexion is in parallel, this tensor is the same in the two rheological components we consider. We also assume that the constitutive law of the elastic element is given by
in which
is a fourth order tensor. Moreover we assume that, the constitutive law of the rigid-elastic element is given by
where
represents the set of constraints and, as usual,
represent the outward normal cone to
K. Denote by
the interior of
K in the topology of
. Then, for stress fields
such that
we have
and, therefore, equation (
101) implies that
. We conclude that this equation describes a rigid behavior. For stress fields
such that
we can have
and therefore, (
101) describes a nonlinear elastic behaviour. An example of set of constraints is the von Mises convex used in [
5,
18], for instance. It is given by
where
represents the deviatoric part of the tensor
and
k is a given yield limit.
We now use relations (
99)–(
101) to write
and, using notation
we obtain the following constitutive law:
The second consitutive law is obtained by connecting in parallel a linearly elastic rheological element with a rigid-elastic rheological element without constraints. Therefore, we keep the notation
,
and
introduced above and we denote by
the stress in the rigid-elastic element. We have
and we assume now that the constitutive law of the rigid-elastic element is given by
Here, again
K represents the domain of rigidity of the material, assumed to be a nonempty closed convex subset of
and, in addition,
denotes the projection operator on
K and
is a given elastic coefficient. Note that for stress fields
such that
we have
and, therefore, (
105) implies that
which shows that this equation describes a rigid behavior. For stress fields
such that
we have
.
We now use relations (
105), (
104) and (
100) to write
and, using notation
in order to underline the dependence of the strain field on the coeficient
, we obtain the following constitutive law:
A brief comparation between the constitutive laws (
106) and (
103) reveals the fact that (
103) is expressed in terms of inclusions and involves unilateral constraints. In contrast, the law (
106) is in a form of an equality and does not involves unilateral constraints. For these reasons we say that the (
106) is more regular that the constitutive law (
103). Consider now the following assumptions.
Our main result in this section is the following.
Theorem 7. Assume (107) and (108). Then, for every stress tensor there exists a unique solution to inclusion (103) and, for every and , there exists a unique solution to equation (106). Moreover, in as .
Theorem 7 is a direct consequence of Theorem 5. In addition to the mathematical interest in this theorem, it is important from mechanical point of view since it shows that:
a stress field
gives rise to a unique strain field
associated with the constitutive law (
103);
a stress field
gives rise to a unique strain field
associated with the constitutive law (
106);
the constitutive law (
103) can be approached by the more regular constitutive law (
106) for a small elasticity coefficient
.
Author Contributions
Conceptualization, Sofonea.M.; methodology, Sofonea M. and Tarzia D.A.; original draft preparation, Sofonea. M.; review and editing, Tarzia D.A.
Funding
This research was funded by the European Union’s Horizon 2020 Research and Innovation Programme under the Marie Sklodowska-Curie Grant Agreement No 823731 CONMECH
Conflicts of Interest
The authors declare no conflict of interest. The funders had no role in the design of the study; in the collection, analyses, or interpretation of data; in the writing of the manuscript; or in the decision to publish the results.
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