2. Fundamental Concepts -Open Sets and Topology
A pair
that consists of a set
and family
of subset of
that match the following criteria is topological space [
10]:
The pair is referred to as a topological space, and the subset of that belongs to is referred to as open sets in the space. The opposite of the pair is called the closed subsets of are those that fall into the family , the family of open subsets of is often referred to as topology of .
and W is closed } is known as -closure of a subset .
It appears that the smallest closed subset of that contains S is . Keep in mind that S is only closed if and when .
and V is open } is known -interior of a subset .
It appears that is the union of all open subsets that contain in S. Keep in mind that S is only open if and when . Additionally, the boundary of a subset is denoted as .
Assume that S is a subset of , a topological space. Let ,, and be interior, closure, and boundary of S, In that order . If then S is exact , if not, S is rough. If and only if , then it is evident that S is exact.
Definition 1 ([
3]).
Let be a topological space the subset is referred to as Preopen if .
The opposite of Preopen set is Preclosed set. As we that indicate the set of all Preopen and Preclosed sets by and .
Remark 1. Every topological space , has the property .
Definition 2 ([
9]).
Let S be a subset of a topological space . The δ- closure of S is defined as follow and . A set S is referred to as δ-closed if .The opposite of a δ-closed set is δ-open.
Observe that .
Definition 3 ([
11]).
If S is a subset of a topological space and , then S is -open.
is the family of all -open sets of . -closed is the complement of -open.
The -closure of S is cl, which is the intersection of all -closed sets that contain S.
The -interior of S is represented by int and is the union of all -open sets that are contained in S.
Lemma 1 ([
17]).
The following hold for a subset S of a topological space .
.
.
.
.
3. Rough Set
Rough set theory was inspired by the necessity of express subsets of a universe in terms of equivalency classes of a partition of that universe. A topological space known as approximation space
is characterized by the partition, where
is an equivalency relation and
is a set known as the universe [
1]. The terms chunks, granules, and elementary sets are also used to describe the equivalency classes of
. To denote that an equivalency class contains an
, we will use
. Two operators in the approximation space are considered.
Referred to as, respectively, the lower and upper approximations of S⊆. Furthermore, let represent the negative region of S, and represent the positive region of S, represent the boundary region of.
If we assume that is a finite, nonempty universe and that , then the accuracy measure can also be used to quantify the degree of completeness as follows:
Where the set’s cardinality is represented. The degree of knowledge completeness is attempted to be expressed via accuracy metrics. is capable to depict the size of the data sets boundary region, but the knowledge’s organizational structure is more difficult to depict. Rough set theory has the essential advantage of being able to handle categories that, given a knowledge basis, cannot be properly specified. The rough sets framework can be used to measure the properties of potential data sets, we may quantify imprecision and convey topological characterization of it, with the help of the following.
If and , then S is roughly - definable, and indicated by .
If and , then S is internally -undefinable, and indicated by ,
If and , then S is externally - undefinable, and indicated by ,
If and , then S is totally - undefinable, and indicated by .
We can characterize rough sets in terms of the boundary region’s size and structure by utilizing
and the previously given categories. Viewed as a particular instance of relative sets, rough sets are associated with the notion of Belnap’s logic [
7].
Remark 2. We indicate the relationship between a class of Preopen sets O and a topology τ on that was utilized to obtain a subbase using . Furthermore, we represent - approximation space by .
Definition 4. If be a -approximation space, then the -lower (resp., -upper) approximation of each nonempty subset S of follows: as:
We are able to obtain the -approximation operator as shown below.
From the provided relation , find the right neighborhood , where .
Taking right neighborhoods as a sub-base to obtain the topology τ.
Preopen set family obtained by using open sets in topology τ "from Definition 1."
To obtain - approximation operators, use the set of all Preopen sets ( see Definition 4).
Proposition 1. For every in any - approximation space the following are hold :
Proof. (2) It the follows from
. □
Definition 5. Assume that S and that is a - approximation space and. Then there are the memberships , , , and , which are defined as , strong, weak, -strong, and -weak memberships respectively.
iff ,
iff ,
iff ,
iff .
Remark 3. As stated by Definition 5, - lower and - upper approximation of a set is possible to write as
Definition 6. Assume that and that is a - approximation space. the - accuracy measure of S, defined as follows;
Definition 7. The subset of any - approximation space is referred to as;
If and , then roughly - definable, and indicated by ,
If and , then internally - undefinable, and indicated by ,
if and , then externally - undefinable, and indicated by ,
If and , then totally - undefinable, and indicated by .
Remark 4. For any - approximation space the following hold:
,
,
,
.
4. A Novel Approach to Rough Categorization Using the -Open Set
Remark 5. A subbase for a topology τ on and a class of of all -0pen sets by are indicated, along with the relationship that was utilized to obtain them. Furthermore, we designate the approximation space by .
Example 1. Assume a universe and a relation defined as thus as well . Consequently, the topology related to this relationship is as well .is a - approximation space.
Definition 8. Assume that () is - lower approximation as well - upper approximation for every nonempty subset S of , the definition is:
,
.
Definition 9. Assume that() is - accuracy measure of S specified as follows
Theorem 1. Given any binary relation on , which generates a topological space , we obtain .
Proof.
, that is, .
Furthermore, , that is, .
Consequently, . □
Definition 10. Assume that the - approximation space is (. With consider to any , the universe can be divided into 24 areas as follows.
, which is the internal edg of S.
, which is the -internal edg of S.
, which is the - internal edg of S .
, which is the external edg of S.
, which is the - external edg of S.
, which is the - external edg of S.
b(S) = , which is the boundary of S.
= , which is the - boundary of S.
, which is the - boundary of S.
, which is the exterior of S.
, which is the - exterior of S.
, which is the - exterior of S.
.
.
.
.
.
.
.
.
.
.
.
.
Remark 6. An extension of the study of approximation space is the study of - approximation space (Figure 1). Due to the components of the areas [], [], and[] will be defined well in S, In Pawlak’s approximation, however, this point was undefinable. Additionally, the component of the areas [],[],additionally [] don’t belong in S, even though Pawlak’s approximation space doesn’t provide these components a clear definition.
Proposition 2. If S is any subset of , then the following holds for any - approximation space:
Proof. (2) It the follows from
. □
Definition 11. Assume that and that ( is a - approximation space. Then there are the memberships ,, which are defined as, - strong and - weak membership respectively
Remark 7. As stated by definition 10 , - lower and - upper approximations of a set is possible to write as:
Remark 8. Assume that ( is a - approximation space, . Then
The converse of Remark 8 It might not always be the case, as demonstrated by the example below.
Example 2. In example 1. Let N=, we have N but N. Let N =, N but N. Let N = then we have N but N. Let N =, N but N.
Example 3. We can deduce from example 1 with the following table, which displays the degree of accuracy measure , -accuracy measure additionally - accuracy measure for some subset of .
The set has a degree of precision of 50% according to the accuracy measure, and 100% according to the - accuracy measure. Furthermore, the set according to - accuracy measure equal to 75% and according to - accuracy measure equal to 100%. Thus, -accuracy measures are superior to accuracy and -accuracy metrics.
We study
- rough inclusion, using the rough inclusion method that Novotny and Pawlak developed in [
19,
20].
Definition 12. Assume that ( is a approximation space where S,. Then we state:
S is - roughly bottom included in N if ,
S is - roughly top included in N if ,
S is - roughly included in N if (1) and (2).
Example 4. As shown in Example 1, is - roughly bottom included in .
Furthermore is - roughly top included in . Additionally is - roughly included in
Definition 13. Assume that ( is - approximation space, a subset S of is referred to as
- definable when ,
- rough when
Example 5. For any - approximation space as in Example 1. We have the set is - exact.
Definition 14. The subset of any - approximation space is referred to as;
If and , then roughly - definable, and indicated by ,
If and , then internally - undefinable, and indicated by ,
if and , then externally - undefinable, and indicated by ,
If and , then totally - undefinable, and indicated by .
Remark 9. Assume that is a - approximation space. These are on hold :
,
,
,
.
Example 6. As shown in Example 1, the set but .The set but . The set and . the set but .
Proposition 3. Assume that the - approximation space is . After that
Proof. Evident.
As demonstrated by the example that follows, the converse of every part of proposition 3, might not always hold. □
Example 7. Consider as an - approximation space for in example 1. Consequently the subset is - exact but not -exact, while is P-rough but not -rough.
Proposition 4. Assuming that and any - approximation space .Next
,
,
If then and
Proof.
Assume , meaning that . And after that, there in such a manner that . So , therefore , furthermore, assume additionally, by definition of , then for everyone . Therefore .
Adheres directly.
Assume , meaning that however , so and , then . Additionally let this implies that afterward, there are and meaning that, there is and which suggest , so . Consequently .
□
Proposition 5. Assuming that and any - approximation space .Next:
,
,
,
,
,
.
Proof.
Assume meaning that . Consequently, there in such a manner that . And after that, there such that . So . So . Consequently .
Comparable to (1).
By definition , That suggests that .
. From (1), (2) and (3), we get .
Since and by (3) we have , then .
Since and by (4), we have , then .
□
Proposition 6. Assume that is a - approximation apace and . Then
,
,
,
.
Proof.
Given that we have and . And after that and by (3) in the Proposition 4, then .
(2), (3) and (4) the same as (1).
□
Theorem 2. Assuming that and any - approximation space If S is -definable. The next items are then held.
- (1)
.
- (2)
.
Proof.
-
Evidently . To include the opposite, assume , that implies is . And after that, there in such a manner that . We present three instances:
- (a)
If and is a -open the set, then .
- (b)
If , then and , thus .
- (c)
If . Since and is an -open the set, then , each in the previously mentioned condition, therefore , then , since S is - definable. Thus, in three instances .
Evidently . We demonstrate the opposite inclusion, assume , then denotes and , in which V is an -open the set and suggests for every . Consequently . Therefore .
□
Theorem 3. Assuming that and any - approximation space . Afterwards, the following are held.
,
.
Proof.
In accordance with propositions 4 (1) and 6 (2), we . Then . However, since and the union of an -open set and a closed set is -closed, and after that . Consequently .
Given that an open set’s intersection with and an -open set is -open, . However, by applying proposition 6 (3), . Consequently .
□
Lemma 2. For any -approximation space furthermore, for everyone , the state of and infers .
Proof. According to the definition of -upper approximation a set is a -closure of this set, furthermore is a -closed set containing c (according to the condition) but is the tiniest -closed set containing c, thus . Therefore By symmetry, the opposite inclusion occurs . therefore we obtain . □
Lemma 3. Assume that be a -approximation space, where each -open subset S of is -closed, Then therefore for every .
Proof. If , then there is a -open set V include c such that which suggests that but is a -closed set additionally is a -open set does not include c, thus . Therefore . □
Proposition 7. Assume that be a - approximation space, and all of them -open subset S of is -closed. After that, the family of sets is a division of the set .
Proof. If furthermore , then furthermore . Consequently, by Lemma 3, and furthermore by Lemma 2, as we have and . Consequently . Therefore either or □