2. Method
According to Newton’s law of universal gravitation, the absolute value of the force of gravitational interaction between two objects is
where
m1 and
m2 are the masses of the objects, and
r is the distance between the centers of their masses, and
G = 6.674×10
–11 m
3/(kg∙s
2) is the gravitational constant.
From Newton’s law follows the formula for the gravitational potential Ф (we mean its modulus), which characterizes the gravitational field of an ordinary body:
where
m is the mass of a body,
r is the distance from the body’s center of mass to the point at which the potential is determined. Note that the gravitational potential has the dimension of the square of the velocity, [Ф] = [
υ2] = (m/s)
2.
It should be recalled that the International System of Units (SI) is a composite system that includes, in particular, the m-kg-s system of mechanical units (MKS system) and the m-kg-s-A system of electromagnetic units (MKCA system). The second system differs from the first primarily in that, along with the existing three base units (meter, kilogram, and second), it has a fourth base unit – ampere (A).
For example, in the MKSA system, the elementary electric charge e = 1.6×10−19 C, and the proportionality coefficient, included in Coulomb’s law, k = 9×109 N∙m2/C2.
In 2018, an article [
1] was published that showed that the electromagnetic units of the MKSA system (the ampere, coulomb, ohm, volt, etc.) can be converted using the base units of the MKS system: m, kg, s. In the paper, it was shown that in the MKS system
where
c = 3×10
8 m/s is the speed of light in vacuum, and
F1 = 10
–5 kg∙m/s
2 (or 1 g∙cm/s
2 – the unit of force in the СGS system).
Using these results, it was shown in paper [
2] that the constant
where
υg = (
G/
k)
1/2 = 0.8617×10
–16 m/s is the
elementary speed, i.e., the lowest speed of movement in nature.
Substituting the expression for
G into equation (1), the new formula for the law of universal gravitation was obtained:
or
where
g1 =
m1υg and
g2 =
m2υg are the
gravitational charges of the interacting bodies, and the coefficient
k = 9×10
21 m/kg.
So, we obtained an expression exactly analogous to Coulomb’s law (in the MKSA system):
where
F is the absolute value of the force of electrostatic interaction in a vacuum of two point electric charges
q1 и
q2,
r is the distance between them, and the coefficient
k = 9×10
9 N∙m
2/C
2.
From Coulomb’s law follows the electric potential φ that characterizes the electrostatic field of a point electric charge
q and is defined in a vacuum by the formula
where
r is the distance from the charge to the point at which the potential is determined.
In the MKS system, the electric charge has the dimension of the momentum, [q] = kg∙m/s, and the coefficient k has the dimension [k] = m/kg; thus, the electric potential has the dimension of velocity, [φ] = [kq/r] = [υ] = m/s.
Hence, analogous to the electric potential, we can introduce a new formula for the gravitational potential:
where
g =
mυg is the gravitational charge of a body,
r is the distance from the body’s center of mass to the point at which the potential is determined, the coefficient 9×10
21 m/kg, and the potential Ф
υ has the dimension of
velocity, [Ф
υ] = [
υ] = m/s.
It turns out that we can use this potential to calculate the transition mass from giant planets to brown dwarfs.
As previously mentioned, when the transition mass is reached, the conditions for the start of thermonuclear fusion are formed. An object with such a mass begins to emit the light (electromagnetic waves) that can travel a distance equal to the radius of the observed universe (R). This radius is determined by the formula R=c/H, where H is the Hubble constant. The exact value of this constant is not yet known; measurements give a value of H ≈ 70 (km/s)/Mpc (1Mpc = 3.0856×1022 m).
Let us assume that for an object with a transition mass
m, at a distance equal to the radius of the observed universe (
r=
R) the potential Ф
υ is equal to the speed of light (Ф
υ=
с). Hence, according to equation (10),
Using the value
H = 70 (km/s)/Mpc = 2.26×10
–18 s
–1, we calculate:
where
MJ = 1.9×10
27 kg is the Jupiter mass.
So, we obtained a value twice the accepted intermediate mass. Therefore, we must finally accept that for an object with an intermediate mass
mi , at a distance
r=
R the potential Ф
υ=
с/2:
Hence, the intermediate mass
Thus, to accurately calculate the transition mass, we need to know the exact value of the Hubble constant.