1. Introduction and Main Results
In this paper, we study the Brezis-Nirenberg problem on H-type groups
where
is a smooth bounded subset with
boundary and
is the Kohn Laplacian. Here
is an even number and
is the homogeneous dimension of
G,
is the critical exponent in the sense of the
Folland-Stein inequality.
The classical Brezis-Nirenberg problem set on Entire space
is a model-based problems of the classical Yamabe problem (prescribed curvature problem) related to the Riemann manifolds, see Yamabe [
30]. It says that for a Riemannian manifold
, finding a conformal metric
such that the scalar curvature
is a constant. If
is a new metric conformal to
g, the scalar curvature
of
is given by
If
is a constant, then the problem is equivalent to finding a positive
solution
u to the Yamabe equation:
This problem has the following nice variational formulation. Consider the constrained variational problem
Then the Yamabe problem becomes the following problems:
(a) depends only on the conformal class of g.
(b) , in which the sphere has the standard metric.
(c) If , then the infimum is attained by a positive solution. Thus the metric has constant scalar curvature .
Thanks to the contributions of Aubin [
1] and Schoen [
25], these issues have been completely resolved. The proof of (a) consists of the fundamental observation that problem (
3) is conformally invariant. The proof of (b) begins with a thorough understanding of the special case of the sphere
in
:
The conformal change of variables given by stereographic projection converts the variational problem on
to the more familiar problem on
:
In other words, by a stereographic projection,
. While
is the sharp constant of the Sobolev inequality on
:
and it is attained by a Talenti bubble.
Therefore, (c) can be easily proved by transplanting an approximate extremal function from to a small neighborhood on M.
Actually, when further examining the apparent solution, Trudinger [
27] pointed out the problem of lacking compactness. Therefore, Briezs and Nirenberg [
4] proposed a detection of the Yamabe equation from an analytical perspective involves constructing model-based problems:
where
is a bounded domain and
is the Sobolev critical exponent. This problem has been solved in different domains, see [
6,
7,
13].
As we are aware, similarly to how Riemann manifolds function in Classical Mechanics, the Heisenberg group plays a significant role in Quantum Mechanics due to its noncommutative structure, see [
5]. Additionally, the Heisenberg group is considered as a Cauchy-Riemann (call CR short) manifold, intersecting complex analysis, differential geometry, and the theory of partial differential equations, see [
10]. On the other hand, since Wells [
29] established the CR structure on complex manifold, Chern, Moser [
8], Webster [
28] and Tanaka[
26] found a complete system of analytic invariant for two real analytic real hypersurfaces in complex manifold to be locally equivalent under biholomorphic transformation, one then can define the unique connect form
of any CR manifold, and hence, the Webster scalar curvature
. Therefore, there are far-reaching analogies between conformal and CR geometries, see [
20]. The CR-Yamabe problem says that for a CR manifold
, finding a contact form
such that the Webster scalar curvature
is a constant. If
is a new contact form conformal to
, the Webster scalar curvature
of
is given by
If
is a constant, then the problem is equivalent to finding a positive
solution
u to the CR-Yamabe equation:
Consider the constrained variational functional
Then the CR-Yamabe problem becomes the following problems:
(d) depends only on the conformal class of .
(e) , in which the sphere has the standard CR structure.
(f) If , then the infimum is attained by a positive solution. Thus the metric has constant Webster scalar curvature .
The proof of (d-f) is quite similar to the classical case. By the Cayley transform, the variational problem on
can be transformed into the variational problem on
This relates to the Folland-Stein inequality on
Building on Obata’s proof [
24], Jerison and Lee [
21] demonstrated the uniqueness of positive optimizers by deriving a Bianchi identity for the CR function that undergoes a conformal transformation. As a model-based problems, Citti [
9] also consider the Brezis-Nirenber problem on
where
is a bounded domain,
is the homogeneous dimension of
and
is the critical exponent of Folland-Stein inequality. Readers can refer [
16,
18] to the nonlocal case.
In the 1980s, Kaplan [
22] introduced an H-type group in connection with hypoellipticity questions, showing similarities with the Heisenberg group but with more intricate properties, see
Section 2. Particularly, in paper [
22], Kaplan also established the similar Folland-Stein inequality on H-type group
G
where
is the Haar measure on
G. Following this result, Han and Niu [
19] established the corresponding Hardy-Sobolev type inequalities on H-type group. Interested readers can refer to [
33] for the Caffarelli-Kohn-Nirenberg inequality, and to [
23] for the Stein–Tomas type inequality on H-type group.
For further insights on the H-type group, Garofalo and Vassilev [
14,
15] presented the Yamabe-type problem concerning this group. Strangely, since Kaplan [
22] determined the explicit form of the optimizers for (
13), the uniqueness of the optimizers has been a longstanding question. Nearly 20 years later, Garofalo and Vassilev [
14,
15] provided a definitive answer when the H-type group is an Iwasawa-type group. Recently, Yang [
31] eventually proved the uniqueness of the optimizer using a sub-critical approximate methods. However, due to the absence of Cayley transform on the general H-type, proving the the non-degeneracy of the optimizer become challenging. As a result, extending the perturbation result of the Yamabe equation from Iwasawa-type groups (see [
32]) to H-type Groups remains unfeasible. This situation prompts us to examine the linear perturbation problem of the critical equation on the bounded domain, that is the Brezis-Nirenberg problem (
1) on the H-type group. As we can see, the solution to the Brezis-Nirenberg problem greatly depends on the dimension and topological properties of the domain, as highlighted in [
6,
7]. Therefore, researching the Brezis-Nirenberg problem on an H-type group with non-homogeneous dimension holds considerable significance. By carefully analyzing and utilizing the variational method, especially the Linking argument, the primary outcome is as follows:
Theorem 1. Let Ω be a bounded domain of G, assume that are the sequence of eigenvalues of on Ω with zero Dirichlet boundary data. Then
(i) for all , (1) has a nontrivial solution.
(ii) for all , , (1) has a nontrivial solution.
Remark 1. Let Ω be a star shaped domain, and , then u is a non-negative solution of (1) implies . This result stems from establishing a significant Pohozaev identity, as shown by Han and Niu [[17], Theorem 3.6]. In the case where Ω is a half-space of H-type groups, Bonfiglioli and Uguzzoni [2] have also derived similar Nonlinear Liouville theorems.
Turing to layout of the paper, in
Section 2, we give some preliminaries knowledge on H-type group. For the sake of clarity, we establish the variational frame and make some compactness analysis in
Section 3. The total proof has been divided into two cases, one is
and another is
. All of these process are completed in
Section 4. Particularly, we prove the first case by a mountain-pass theorem and we prove the second case by a Linking argument.
2. Preliminaries on H-Type Groups
Let’s begin with some basics of Carnot group. Carnot group (in a short
) is a stratified, simply connected nilpotent Lie group of step
r. Denote by
be Lie algebre of
. It is known that
satisfying (see e.e. [
12])
As a simply connected nipotent group,
is differential with
,
, via the exponential map
. There is a natural family of nonisotropic dilations
for
and we define it as follow:
The homogeneous dimension of
, associated with
, is
.
An H-type group
G is a Carnot group with the following properties (see Kaplan [
22]): the Lie algebra
of G is endowed with an inner product
such that, if
is the center of
, then
and moreover, for every fixed
, the map
defined by
is an orthogonal map whenever
. Set
and
. Since
G has step two, we can fix on
G a system of coordinates
such that the group law on
G has the form (see [
2])
for suitable skew-symmetric matrices
’s. Note that
is also a orthogonal matrix, hence
m has to be an even number, see [
2]. The vector field in the Lie algebra
that agrees at the origin with
is given by
and
is spanned by the left-invariant vector fields
,
. Furthermore (see [
2], Page 200, (A.4)),
The horizontal gradient on
G is
. The sub-Laplacian on
G is given by (see [
2], Remark A.6.)
where
The Sobolev space
is the closure of
with respect to the norm
where
is the Haar measure on
G. We remark that the Haar measure on
G, induced by the exponential mapping from the Lebesgue measure on
, coincides the Lebesgue measure on
. Correspondingly, in a bounded domain
, we define the Sobolev space as
.
The Folland-Stein inequality on
G reads that there exist some constant
C such that for each
(see [
11,
20,
21])
More precisely, Yang [
31] obtained the sharp constant
and obtained the uniqueness of the extremal unction
. Namely, set
it has been shown that
satisfies the Yamabe-type equation (see [
14,
15])
or equivalently,
Based on the group law (
14), the nonisotropic dilations
on
G is
For
, the homogeneous norm of
is
With this norm
, we can define the ball centered at origin with radius
R
3. Variational Framework
In order to study the problem by variational methods, we introduce the energy functional associated to (
1) by
Firstly, we check that the energy functional has a mountain structure as .
Lemma 1. If , then satisfies the following properties:
(i) There exists such that for .
(ii) There exists with such that .
Proof. (i) By the Poincare inequality and Sobolev embedding inequality, we have
Since
, we can chose some
such that
for
.
(ii) For some
, we have
for
large enough. Hence we can take an
for some
and (ii) follows. □
Proposition 1.
If , there exits a sequence such that and in at the the minimax level
where
Proof. The proposition is a direct conclusion of Lemma 1 and the mountain pass theorem without condition. □
As
for some
, we then easily check that
satisfies a Link structure. Set
be the sequence of eigenfunctions corresponding to
. We know that this sequence is an orthonormal basis of
and the orthogonal basis of
. We denote
and denote
by the linear subspace generated by the first
j eigenfunctions of
for any
. Note that
is finite dimensional and
, then
satisfies the following properties:
Lemma 2. If for some , then
(i) There exists such that for any with such that .
(ii) for any .
(iii) Let be a finite dimensional subspace of . There exists such that for any with such that .
Proof. (i) By the Poincare inequality and Sobolev embedding inequality, for any
, we have
Since
, we can chose some
such that
for all
with
.
(ii) Let
, i.e.,
, where
,
. Since
is an orthonormal basis of
and
, we have
Then, we get
(iii) Since all norms on finite dimensional space are equivalent, the non-negativity of
gives
for some positive constant
. So,
as
. Hence, there exists
such that for any
with
it results that
. □
Similar to Proposition 1, we have the next proposition for .
Proposition 2.
If , there exists a sequence such that and in at the minimax level
where
and
Now, we are discuss the boundedness of these sequence.
Lemma 3. For any but , if is a or sequence of , then is bounded in . Let be the weak limit of , then is a weak solution of (1)
Proof. It is easy to see that there exists
such that
We firstly prove the case
. For
n large enough, then by (
19) we have
for some
. Thus
is bounded in
.
We Secondly prove the case
. Let
, then for
n large enough we have
for some
, where
,
,
, where
is defined in (
17). It is then easy to verify that
is bounded in
using the fact that
is finite dimension.
Next, we are going to prove that
is a weak solution. Since
is reflexive, up to a subsequence, still denoted by
, there exists
such that
in
as
in
as
. Then
as
. Since
, we have
passing to the limit as
, we obtain
for any
, this means that
is a weak solution of (
1). □
To make sure the weak solution , we shall prove the sequence has a strong convergence subsequence by controlling the energy of the functionals. Before this, we need a Brezis-Lieb lemma to describe the properties of the sequence.
Lemma 4.
Let , be such that , and a.e. in Ω. Then
If replace with any Hilbert space , on has that
Hence if converges weakly to u then (20) holds.
Proof. The proof is similar to the classical case, we refer readers to Brezis-Lieb [
3]. □
Based on this Lemma, we have the following claim.
Lemma 5.
For any and , if is a sequence of with
then has a convergent subsequence.
Proof. Let
be the weak limit of
obtained in Lemma 3 and define
. Then we know
in
and
a.e. in
. By the Brezis-Lieb lemma 4, we know
and
Then, since
and
, we have
Similarly, since
, we have
From (
23), we know there exits a non-negative constant
b such that
and
as
. From (
22) and (
23), we obtain
On the other hand, By the definition of the best constant
in (
15), we have
which deduce that
.
Thus we have either
or
. If
, the proof is completed. Otherwise
, then we obtain from (
24) that
which contradicts with the fact that
. Therefore,
and
as
.
□
To control
and
by some
, we recall some invariant properties of extremal function for the sharp constant
. Since the functional associated the Sobolev inequality is invariant under dilation, define
we then have
Observe that the critical point of
or
is vary closed to the extermal function, we take a cut-off method to estimate every term of
. Without loss of generality, we may assume that
and
for some positive
R. Let
such that
and
,
for all
. Define
we then have the following estimate:
Lemma 6.
where is a positive constant.
Proof. (i) By the define of
, we have
For the second term, we have
For the third term, we have
Hence, (
25) holds.
(ii) Since
satisfies the Yamabe equation (
16), we have
For the second term in the last inequality, we have
For the third term in the last inequality, we have
Hence, (
26) holds.
(iii) A direct calculation shows that
If
, then
if
, then
This implies that (
27) holds. □
Based on the above estimate, we have the following inequality holds.
Lemma 7.
For any , there exists such that
Proof. For the case
and
large enough, we have
For the case
and
large enough, we have
□