We are going to make a correlation, a parallelism between the theory that describes a Kerr-Newman black hole with the theories of the following papers: RLC Electrical Modelling of Black Hole and Early Universe. Generalization of Boltzmann’s Constant in Curved Space-Time, and Electrical-Quantum Modelling of the Neutron and Proton as a Three-Phase Alternating Current Electrical Generator. Determination of the Number of Quarks-Antiquarks-Gluons and Gravitons, Inside a Neutron. We will use these theories to analyse the behaviour of our model.
4.1. Correlation between Kerr-Newman Black Hole vs. RLC Electrical Modelling of a Black Hole
In both models the black holes rotate around their axial axis.
In
Figure 14, we can see an ergosphere, an outer horizon and an inner horizon. We also observe that the outer and inner horizons are cofocal oblate spheroids whose focus is the ring singularity.
In
Figure 15, we can also observe an event horizon and a ring singularity, we can assume that the event horizon is cofocal oblate spheroids and whose focus is the ring singularity.
Under this condition, M² > Q² + a²; The black hole is born and grows, we can say that it represents the first moments of the life time of a black hole.
As the black hole grows, the distance between the outer horizon and the inner horizon decreases.
The particles that enter the black hole pass through the ergosphere, cross the outer horizon and the inner horizon and finally fall into the ring singularity. Inside the ring singularity (r ≤ 0) the bosonic particles move at a speed greater than the speed of light, which generates an additional mass which we represent in our model as – iδ (see equation 41). This additional mass generates a gravitational force that is not attractive and is the gravitational force that gives rise to dark matter.
Let us remember that a black hole grows in the same way as the Tau constant of an RC circuit (equation 40).
We are going to represent the graphs and calculations that describe the growth of a black hole, the complete mathematical development can be found in the paper: RLC Electrical Modelling of Black Hole and Early Universe. Generalization of the Boltzmann constant in curved spacetime.
Now we are going to present the Penrose Diagram:
If we look at
Figure 15, we see that the spheroid that represents a black hole can be divided into two parts, an upper part and a lower part.
If we look at
Figure 17, if we consider the yellow vertical line, we can also divide the graph into two parts, a spatial part representing the right side and a spatial part representing the left side.
If we consider a test particle, we see in
Figure 15 that it can enter the upper part, at the equator of the spheroid, cross the event horizon and head to the upper singularity. There is also another option in which the test particle could enter the lower part of the equator, in the spheroid, cross the event horizon and head to the lower singularity.
If we consider a test particle, we see in
Figure 17, in analogy with
Figure 15, that it can enter the left side of the black hole, in the ergosphere, cross the event horizon, pass through the wormhole region and end up in the antiverse region. There is also another option in which the test particle could enter on the right side of the black hole, in the ergosphere, cross the event horizon, cross the parallel wormhole region and end up in the parallel antiverse region.
If we look at
Figure 15, both currents I₁ and I₂ have a positive charge and move in the opposite direction. We observe that current I₁ moves counter clockwise and generates an upward magnetic field (blue); Current I₂ moves clockwise and generates a downward magnetic field (orange).
Both the electric and magnetic force generated by currents I₁ and I₂ produce a repulsion force between the coils, this is counteracted only by the gravitational force.
If we look at
Figure 17, if we consider a test particle, we see that there is a repulsion force between the left side of the graph and the right side, for example, if a test particle (1) that enters the black hole, enters the ergosphere, enter the wormhole and antiverse; If we consider
Figure 15, by analogy the particle heads upward until it reaches the ring singularity. Now we consider the test particle (2) that enters the black hole, ergosphere, parallel wormhole, parallel antiverse, by analogy to
Figure 15, the test particle heads downward until it reaches the ring singularity. The test particle (1) is directed upward, while the test particle (2) is directed downward, as if both positive particles were under opposite forces.
There is an analogy between graph 15 and graph 17, the upper part of graph 15, from the equator up, corresponds to the left symmetrical region of the vertical yellow line of graph 17; The lower part of graph 15, from the equator downwards, corresponds to the right symmetrical part of the vertical yellow line of graph 17.
Another important analogy that we must highlight is the ring singularity, above the equator in
Figure 15, which corresponds to the antiverse in the left symmetry of graph 17; We must also highlight the ring singularity below the equator in
Figure 15, which corresponds to the parallel antiverse in the right symmetry of graph 17.
Finally, it is important to note that the black hole grows and as it increases in size, the regions of the black hole that we call ergosphere, wormhole (parallel wormole) and antiverse (parallel antiverse) also grow.
Here, it is important to note that although the black hole grows, nothing material comes out of the black hole, therefore we can represent this in
Figure 17 only with the yellow triangle. What is stated here is very important.
- 2.
>2. We are going to perform an analysis for the condition: M² = Q² + a²
The Kerr-Newman geometry is called extremal when the outer and inner horizons coincide:
We see that in this condition there is a single event horizon, which we are going to represent in the following Figure:
Figure 18 Spatial geometry of an extremal Kerr-Newman black hole with charge Q = 08M and spin parameter a = 06M.
We could express the relationship M² = Q² + a² in another way:
M² / (Q² + a²) = 1
This is telling us that the growth of a black hole has a limit, that the amount of matter it devours is limited and if it exceeds that limit it has to be expelled in some way; Therefore, the amount of matter that enters the interior of the ring singularity (antiverse) is limited by the mass M of the black hole.
For example, we could assume that this limit is generally exceeded when a stellar black hole devours a star, a quasar.
Here, it is important to note that although the black hole grows, nothing material comes out of the black hole, therefore we can represent this in
Figure 17 only with the yellow triangle.
- 3.
We are going to perform an analysis for the condition: M² < Q² + a²
We could express the relationship M² < Q² + a² in another way:
M² / (Q² + a²) < 1
In this condition, the event horizon disappears and we say that we have a naked singularity.
In this condition, we can observe that the amount of matter (charge) that the black hole devours exceeds its mass.
We said that the growth of a black hole is limited by its mass M, therefore, the amount of matter that enters a black hole is limited by the mass M, that is, if the black hole devours a greater amount of matter that its mass M, then somehow the black hole has to eliminate the excess matter it is ingesting.
We are going to represent the statement in the following Figure:
Let's interpret what we said in a Penrose diagram.
Figure 20, Let's consider two sets of test particles, the two sets of test particles enter the black hole (ergosphere), one set through the horizon and the other set through the parallel horizon; Now let's look at
Figure 15, one set of test particles enters above the equator of the spheroid and the other set of particles enters below the equator of the spheroid.
Let us remember that we are under the condition: M² < Q² + a²
Figure 20, the first set that was in the parallel universe, enters the black hole (ergosphere) through the parallel horizon, part of that set of particles is devoured by the black hole and ends up in the antiverse and the rest of the particles leave the black hole, crosses the inner antihorizon and ends in the new parallel universe. The second set of particles follows a similar path, it enters the black hole (ergosphere) through the horizon, part of that set of particles is devoured by the black hole and ends up in the parallel antiverse and the rest of the particles leave the black hole. It crosses the parallel inner antihorizon and ends in the new universe.
If we look at
Figure 15, the first set of particles enters the black hole above the equator of the spheroid, part of the set of particles is devoured by the black hole and goes to the ring singularity and the rest of the particles are expelled out of the black hole, upwards. Similarly, the second set of particles enters the black hole through the lower part of the equator of the spheroid, part of the set of particles is devoured by the black hole and goes to the ring singularity and the rest of the particles are expelled from the hole black, down.
Figure 17 represents a black hole that grows, under the condition M² ≥ Q² + a², which is telling us that no matter comes out of the black hole. This is represented by the inverted yellow triangle.
Figure 20 represents a black hole that grows and has an associated relativistic jet, under the condition M² < Q² + a², which is telling us that part of the matter that the black hole devours is expelled. This is represented by the two highlighted triangles; the yellow triangle representing the black hole devouring matter and the orange triangle (white hole) representing the amount of matter ejected from the black hole.
An example of the true meaning of what
Figure 20 represents would be a quasar.
Reissner-Nordström Black Hole, the inflationary instability, under the condition Q > M, at point X, an inflationary instability occurs that produces feedback which generates the relativistic jets. The interior mass is not the only thing that increases exponentially during mass inflation. The proper density and pressure, and the Weyl scalar (all gauge-invariant scalars) exponentiate together.
This is analogous to what happens in a black hole with the Kerr-Newman geometry, part of the mass that enters the black hole ends up in the antiverse (ring singularity) and the rest of the mass is ejected in the form of a relativistic jet, is given for the condition M² < Q² + a².
Under this interpretation, the universe, the parallel universe, the new universe and the new parallel universe actually represent our only universe. See
Figure 20.
Under this interpretation, the antiverse and the parallel antiverse in
Figure 17 and 20, represent in
Figure 15, the ring singularity that is at the top of the equator of the spheroid and the ring singularity that is at the bottom of the equator of the spheroid.
According to our description, the black hole model in
Figure 15 perfectly emulates the black hole model represented in
Figure 20, corresponding Penrose diagram of the Kerr-Newman geometry.
- 4.
We are going to perform an analysis for the condition: M = Mc
Here, we are going to analyse the condition in which the black hole reaches its critical mass Mc.
In the theory of the paper
: RLC Electrical Modelling of Black Hole and Early Universe. Generalization of Boltzmann’s Constant in Curved Space-Time; we put forward the hypothesis of a black hole growth in analogy to an RC electrical circuit that grows according to a constant Tau being defined as:
In a capacitor when its charge reaches the value of 5, we say that the capacitor reached its maximum charge, in analogy to the capacitor, when the black hole reaches the value of 5 it reaches its maximum mass value; Let us remember that a capacitor stores electrical energy and a black hole stores gravitational potential energy.
Let us remember that the mass of a black hole in the theory of the paper:
Rlc Electrical Modelling of Black Hole and Early Universe. Generalization of Boltzmann’s Constant in Curved Space-Time; It is represented by the following equation:
Where M is the total mass of a black hole, m is the baryonic mass; corresponds to dark matter and (i) is the irrational number . This equation is in analogy to impedance of an RC circuit.
To calculate the total energy associated to the black hole, we can introduce its total mass (equation 49) into:
Where E is energy; c represents the speed of light and m represents the mass. This lead to:
We can assume that during the big bang inflation phase baryonic matter was overrepresented compared to dark matter together with an infinitesimal momentum, which would give us from equation (51) the following:
As expected, this result corresponds to the total energy of the universe at the big bang if we consider it to be made of dark matter represented as a reactance in an RC circuit.
The positive value of E is determined by matter, there is no antimatter inside a black hole.
If we consider charge as a fundamental property of matter, , represents the amount of relativistic dark matter inside the black hole at the time of disintegration.
If we consider mass as a fundamental property of matter, , represents the amount of relativistic dark matter inside a black hole, which exerts a repulsive gravitational force at the moment of disintegration. This repulsive gravitational force is what generates the cosmic inflation and dark energy after the Big Bang.
At time T0, when the black hole disintegrates and the Big Bang occurs, roughly all matter was dark matter. Relativistic dark matter.
We could also consider a universe at infinity proper time in which baryonic matter is dominant over dark matter, which would transform equation (51) back into equation (50) but with baryonic matter.
Here we put forward the hypothesis that the big bang is the convolution of the energy released by disintegration of the black hole with the space-time surrounding the black hole, being defined as:
Where is the total mass of a black hole, Ɛ is the space-time surrounding the black hole and * is the convolution symbol.
Equation (54) can be simplified and considered analogous to an RLC circuit.
Where RC represents a black hole and L represents the space-time around a black hole.
the resolution of the quadratic equation of the RLC circuit will determine how space-time will expand after the Big Bang and the bandwidth of the equation will give us the spectrum of gravitational waves that originated during the Big Bang.
The growth of the black hole from its birth until it reaches the value of 5
is represented in
Table 2 and
Figure 16.
- a)
In item 1 of the
Table 1, for the following parameters, T = 10¹³ K, Cɢ = C = 310⁸ m/s, calculating we get the following values:
m = 6 10³⁰ kg, baryonic mass.
δ = 0, dark matter mass.
M = m = 6 10³⁰ kg
Rs = 8.89 10³ m, Schwarzschild radius.
b) In item 9 of the
Table 1, for the following parameters, T = 5 10²⁶ K, Cɢ = 3 10²¹ m/s, C = 310⁸ m/s, calculating we get the following values:
m = 1.20 10⁵⁶ kg, baryonic mass.
δ = 1.20 10⁸² kg, dark matter mass.
M = δ = 1.20 10⁸² kg
Rs = 1.77 10²⁹ m, Schwarzschild radius.
c) It is important to emphasize, for the time t equal to 5τ, at the moment the disintegration of the black hole occurs, the big bang originates, the total baryonic mass of the universe corresponds to m = 10⁵⁶ kg.
d)
It is important to highlight, for time t equal to 5τ, at the moment in which the disintegration of the black hole occurs, the big bang originates, the total mass of the dark matter of the universe corresponds to δ = 10⁸² kg.
It is important to highlight the following, when scientists calculated the total baryon mass of the universe, they gave them the following value m = 10⁵⁴ kg, in our calculation, the total baryon mass of the universe gave the following value, m = 10⁵⁶ kg; 100 times greater, I think the difference between the calculations is in the order taking into account the complexity of the calculation.
Figure 16, shows the growth of the tau (τ) constant, as a function of speed vs. temperature.
If we look at
Figure 15, we see that the upper and lower ring singularity are formed by positively charged bosons.
If we consider the electric field E, both (ring singularity) exert a repulsive force. If we consider the magnetic field B, both (ring singularity) exert a repulsive force. Therefore, the only force holding the black hole together is the gravitational force. Above the critical mass of the black hole, the force of repulsion of the electric field and the magnetic field Fr is greater than the force of gravitational attraction Fg, the disintegration of the black hole occurs, that is, a white hole is produced. What we call the Big Bang, this process gives rise to cosmic inflation.
Next, we are going to explain the process that gives rise to cosmic inflation.
Cosmic Inflation
Let's look at
Figure 17 and 20, consider that we move only in the vertical Y time axis, the X axis of space is null. If we consider the instant of time To⁻, we observe that we are in a black hole; If we consider the instant of time To⁺, we observe that we are in a white hole. The instant of time To is an inflection point at which the transition from a black hole to a white hole occurs.
Now let's consider a test particle (1) that moves in the X axis, the Y time axis is null. We begin our movement on the right side through the parallel antiverse, we continue to the left and cross the region of the parallel wormhole, until we reach the inflection point.
Now let's consider a test particle (2) that moves in the X axis, the Y time axis is null. We begin our movement on the left side along the antiverse, we continue to the right, we cross the wormhole region, until we reach the inflection point X.
Let us observe that the test particles (1) and the test particle (2) are at the inflection point, but cannot exceed it.
Now, if we analyse the inflection point, we see that it is a space-type point, its trajectory is space-type, this implies that in order to cross it we need to move at a speed greater than the speed of light, v > c.
If we analyse section 2.9, Antiverse; We see that there is a region for negative radii, r < 0 which corresponds to a negative mass, M < 0.
Later we will analyse the importance of negative mass.
Now we will analyse
Figure 15, we will use two test particles for our analysis, the test particle (1) and the test particle (2). We will consider that the test particle (1) is directed towards the upper singularity ring and the test particle (2) is directed towards the lower singularity ring.
The test particle (1) that is in the upper singularity ring cannot go to the lower singularity ring.
The test particle (2) that is in the lower singularity ring cannot go to the upper singularity ring.
Therefore, in the black hole model represented in
Figure 15, there is also an inflection point.
Here, we are going to hypothesize that the black hole reaches its critical mass Mc, collapses, disintegrates and transforms into a white hole, this process generates cosmic inflation.
This is the only condition in which a test particle can cross the inflection point whose velocity v > c.
If we look at
Figure 20, at time To, the amount of matter in the black hole is the same as that of the white hole. We can deduce this by comparing the orange triangle with the yellow triangle.
There is a second condition in which a test particle can cross the inflection point, it is when a black hole behaves like a quasar, generating relativistic jets. In this condition that we have already analyzed, the inflection point exhibits a feedback inflationary instability, which is what generates the relativistic jets and occurs for the condition M² < Q² + a²
Now we are going to analyse the importance of negative mass, M < 0 (Antiverse), in the origin of cosmic inflation.
We said that the mass of a black hole can be represented in analogy to that of an RC circuit as follows:
Where M is the total mass of a black hole, m is the baryonic mass; δ corresponds to dark matter and (i) is the irrational number √(-1).
We can represent this equation in the following way:
In equation 58, we see that the mass of dark matter can be represented as a negative mass.
We said that a black hole grows like a capacitor, following the Tau constant.
In item 9 of the
Table 1, for the following parameters, T = 5 10²⁶ K, Cɢ = 3 10²¹ m/s, C = 310⁸ m/s, calculating we get the following values:
m = 1.20 10⁵⁶ kg, baryonic mass.
δ = 1.20 10⁸² kg, dark matter mass.
M = δ = 1.20 10⁸² kg
Rs = 1.77 10²⁹ m, Schwarzschild radius.
These values correspond to the moment of time To, in which the black hole reaches its critical mass Mc, collapses, disintegrates, transforming into a white hole.
We will use these values to calculate your Plank Length.
At instant To, the Planck length inside a black hole (white hole) corresponds to Lp = 1.28 10⁻⁵⁴ m.
If we consider the Planck length Lpɛ, the minimum length of space-time, like a spring and due to the action of v > c (300,000 km/s), this length decreases in values of Lpɢ, that is, Lpɢ < Lpɛ, allowing us to imagine the immense forces involved in compressing space-time of length Lpɛ into smaller values of space-time Lpɢ. The immense energy stored and released in the spring of length Lpɢ, to recover its initial length Lpɛ, is the cause of the exponential expansion of space-time in the first moments of the Big Bang.
At time T0, when the black hole disintegrates and the Big Bang occurs, roughly all matter was dark matter, relativistic dark matter. This is represented in equation (52).
4.2. Inside a Black Hole
We are going to use the paper: Proton decay and inverse neutron decay, we will use the new particles proposed in this article to determine what really exists inside black holes.
The new proposed particles are the following:
Dproton
Protoniu
Dneutron
Neutroniumd
In the following Figure we are going to present the main characteristics of these particles along with those of the proton and the neutron for comparison.
We said that the collapse of a star of more than 25 solar masses produces a black hole of 3 solar masses.
In section 3, Modelling of a black hole; we calculated the equivalent neutron/black hole model, which gave us an equivalent neutron mass of 300 MeV/c².
Taking into account the above and considering the equivalent neutron/black hole model, we are going to hypothesize that the collapse of a star larger than 25 suns produces a black hole of 3 solar masses, which contains the neutroniumd particle inside.
We are going to show the graph of the neutroniumd particle:
If we look at
Figure 23, the
neutroniumd particle is made up of three D quarks, matter, it does not contain antimatter; the configuration of these three D quarks is analogous to that of an electric generator, that is to say that each quark can be represented by three vectors out of phase by 120 degrees whose vector sum is zero and whose scalar sum is (-1).
As seen in
Figure 23, the
neutroniumd particle has a mass of 443.10 MeV/c².
The scalar charge of the neutroniumd particle is (-1) but the vectorial charge is zero (0). In other words, the black hole would be formed by negatively charged particles but whose vector sum is zero (0). The distribution of the D-quark vectors inside the black hole is such that the resulting charge on the black hole is zero (0).
In the following graph, we are going to represent the black hole model formed by neutromiumd particles.
It can be seen in
Figure 24 that negatively charged particles enter the black hole and positively charged particles are repelled from the black hole.
At this stage, the black hole grows by devouring negatively charged particles.
As the black hole grows, the mass, pressure, density, etc. increases and another transformation occurs inside the black holes.
We are going to analyse the following transformation that happens inside black holes.
Let's hypothesize the following, as a black hole grows and reaches a critical point of pressure, volume, temperature, density, etc., the neutroniumd particle decays into the protoniu particle.
This decay of the neutroniumd particle in the protoniu particle is very important and explains the jets that quasars produce.
If we compare
Figure 23 and 25, we observe that the mass of the Neutroniumd particle is 443 MeV/c² and the mass of the protoniu particle is 253 MeV/c².
We observe that the D quarks have to decay into U quarks, this is analogous to βˉ decay, therefore electrons, antineutrinos and electromagnetic energy will be produced.
Neutroniumd → protoniu + e⁻ + ṽ + ∆E
Quark D → Quark U + e⁻ + ṽ + ∆E
Inside a black hole the neutroniumd particle decays into the protoniu particle.
Electrons, antineutrinos and electromagnetic radiation are sent in the jet, this would explain why the jet particles are so collimated.
The relativistic jet could be explained for the condition M² < Q² + a², in which there is a naked singularity.
Along with the jet, we must include the particles that are expelled by the action of the magnetic field of the accretion disk.
When the black hole is formed by the neutroniumd particle, the magnetic field B, forces negative particles into the interior of the black hole.
When the black hole is formed by the protoniu particle, the magnetic field B, forces positive particles to enter the interior of the black hole.
In other words, we have black holes formed by negative charges neutroniumd and black holes formed by positive charges protoniu.
According to this theory, the relativistic jet of quasars is produced when the neutroniumd particles, formed by the D quark, decay into the protoniu particle, formed by the U quark, inside the black hole.
If we compare
Figure 22 - Equivalent Neutron/ Black Hole with
Figure 25 - protoniu; We observe that the masses are approximately equal (300 ≈ 253) Mev/c².
In the following graph, we are going to represent the black hole model formed by protoniu particles.
Black holes can be formed by negatively charged particles (neutroniumd) or positively charged particles (protoniu), however, it is important to know that the net charge of black holes is zero, due to their vector configuration, whether they are formed by positively or negatively charged particles.
Another important characteristic of black holes is that they are formed by matter and do not contain antimatter, the process of formation of a black hole separates matter from antimatter.
If we look at
Figure 13, 15, 24 and 26; We see that we write 'Black Hole / Magnetic Monopole', this is due to the following: if we carefully analyse our black hole model, they behave the same as magnetic monopoles.