An important result proved in Ref. [
5] has to do with the spectral theorem for the twist operator
. In particular, within the abstract language of Hilbert space operators, Simon & Mukunda proved that
where the eigenket
position representation coincides with the LG beam of Eq. (
4), i.e.,
From Eq. (
12), it turns out that the spectrum of the twist operator
is highly degenerate. It is worth introducing two auxiliary integer parameters, say
n and
ℓ, defined as
,
, so that
In the following, given the one-to-one correspondance
, the eigenket
will be denoted by
in place of Eq. (
14), without confusion. With these notations, Eq. (
12) will be recast as
The high spectral degeneration of the twist operator represents one of the principal technical problem to be addressed, for the conditions under which a given bonafide Schell-model CSD can or cannot be twistable, to be established. In particular, the spectrum of the twist operator consists in only two eigenvalues, namely
and
, each of them infinitely degenerate. More precisely, the Hilbert space
can be thought of as the union of two subspaces, say
, defined as follows:
i.e., each of them generated by all eigenkets corresponding to the same value of the eigenvalue. It is a well known fact that, since the operators
and
commute, the ket
must itself be an eigenket of
corresponding to the eigenvalue
. In fact,
In Ref. [
8], it was conjectured that, for any radial degree of coherence
, the modes of the twisted CSD
of Eq. (
3), coincide with the modes of
. One of the scopes of the present paper is also to provide a mathematical justification of it. In order to better clarify the terms of the problem, consider the following case, namely
, where
represents a real parameter which will be let run within the interval
(the choice
corresponds to a Gaussian spectral degree of coherence, as for example in the classical GSM case). Consider then the fundamental state
, such that
Then, it turns out
1
and it is not difficult to check that such wavefunction corresponds to an eigenket of the twist kernel
, with eigenvalue equal to
. Moreover, in the limit of
(radial symmetry) the state
becomes proportional to
, as conjectured in [
8]. More precisely,
If
, the state
is expected to belong to the subspace
defined into Eq. (
16). Accordingly, it is natural to write
where, since
, only
even values of the index
would be involved into the double series in Eq. (
21). As it will be discussed in Sec. 4, the possibility of finding such a representation would allow, in principle, to solve the degenerate eigenvalue problem for the
operator and, consequently, to assess its (semi)positive definitiness.
The strategy pursued in the present work is to extract the complete representation of the twisted operator
in terms of the orthonormal basis of the twist operator
, similarly as done in Eq. (
21), but for a typical state
. To this end, the main technical problem is the evaluation of the typical matrix element
. In the next section, it will be shown that the matrix element can be expressed in terms of the inner product between the degree of coherence
and a suitable LG mode of Eq. (
4). To this end, the results of an important paper, published in 2008 by Van Valkenburgh [
10], will be employed. In spite of the strong mathematical character of all steps, we preferred not to give them the aspect of an appendix, but rather, due to their key role, to arrange them into a section which indeed represents the technical core of the present paper.